NEET · Chemistry —

Chemical Bonding and Molecular Structure appeared 3 times across 1 year — 6.7% of Chemistry. This question is from Formal Charge Calculations.

Year 2024 Total
Questions 3 3
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The correct formal charges on oxygen atoms numbered 2, 1 and 3 respectively are:
Ozone molecule oxygen atoms numbered diagram for Q86 - JEE Main 2026 Morning
Lewis structure of ozone with numbered oxygen atoms 1, 2, and 3.

Solution & Explanation

Related Formula
Formal Charge = V - L - (S)/(2)
Core Logic

For Oxygen 2 (double bonded terminal): FC = 6 - 4 - (4)/(2) = 0. For Oxygen 1 (central atom): FC = 6 - 2 - (6)/(2) = +1. For Oxygen 3 (single bonded terminal): FC = 6 - 6 - (2)/(2) = -1.

Step 1: Conclusion

Formal charges on 2, 1, 3 are 0, +1, -1 respectively.

Pattern Recognition

Standard Lewis structure of ozone: central oxygen = +1, single-bonded terminal = -1, double-bonded terminal = 0.

Chapter Mix

Class 11 Chemistry: Chemical Bonding and Molecular Structure

Formal charge calculation diagram for ozone
Lewis structure of ozone with numbered oxygen atoms 1, 2, and 3.

Reference Study Guides

Chemical Bonding And Molecular Structure

More Chemical Bonding and Molecular Structure Previous-Year Questions

Q54 neet_2024_05_may_morning VSEPR Theory and Molecular Geometry
Identify the correct statement about ClF₃ from the following options:
  • A. (1) It has a trigonal pyramidal geometry with two lone pairs on Cl atom.
  • B. (2) It has T-shaped geometry with two lone pairs on Cl atom.
  • C. (3) It has a planar trigonal geometry with two lone pairs on Cl atom.
  • D. (4) It has T-shaped geometry with three lone pairs on Cl atom.

Solution

Related Formula
Steric Number = (7 + 3)/(2) = 5 (sp³d hybridization)
Core Logic

For ClF₃: Central atom Cl has 7 valence electrons. 3 bond pairs + 2 lone pairs = 5 electron pairs. Geometry based on trigonal bipyramidal arrangement gives a bent T-shape due to two equatorial lone pairs.

Step 1: Conclusion

Statement (2) is correct.

Pattern Recognition

AX₃E₂ molecules always exhibit a bent T-shaped geometry.

Chapter Mix

Class 11 Chemistry: Chemical Bonding and Molecular Structure

Q69 neet_2024_05_may_morning Covalent Bonds and Lone Pairs
Match List I with List II:
List I (Molecule)List II (Bonding description)
A. C₂H₄I. 3 σ bonds, 2 π bonds
B. C₂H₂II. 3 σ bonds, one lone pair
C. CH₄III. 4 σ bonds
D. NH₃IV. 5 σ bonds, 1 π bond
Choose the correct answer from the options given below:
  • A. (1) A-IV, B-I, C-III, D-II
  • B. (2) A-III, B-IV, C-II, D-I
  • C. (3) A-I, B-II, C-IV, D-III
  • D. (4) A-II, B-III, C-I, D-IV

Solution

Related Formula
Single bond = 1σ, Double bond = 1σ + 1π, Triple bond = 1σ + 2π
Core Logic

A. C₂H₄ arrow 5σ bonds, 1π bond (IV). B. C₂H₂ arrow 3σ bonds, 2π bonds (I). C. CH₄ arrow 4σ bonds (III). D. NH₃ arrow 3σ bonds, 1 lone pair (II).

Step 1: Conclusion

Matches: A-IV, B-I, C-III, D-II.

Pattern Recognition

Count sigma, pi bonds, and lone pairs for simple hydrocarbons and ammonia.

Chapter Mix

Class 11 Chemistry: Chemical Bonding and Molecular Structure

More Chemical Bonding and Molecular Structure Questions — neet_2024_05_may_morning

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