Chemical Bonding and Molecular Structure Previous Year Questions — NEET Chemistry

3 past-year Chemical Bonding and Molecular Structure questions from NEET (Chemistry).

Q54 (2024)

Identify the correct statement about $ClF_3$ from the following options:
  1. (1) It has a trigonal pyramidal geometry with two lone pairs on Cl atom.
  2. (2) It has T-shaped geometry with two lone pairs on Cl atom.
  3. (3) It has a planar trigonal geometry with two lone pairs on Cl atom.
  4. (4) It has T-shaped geometry with three lone pairs on Cl atom.
### Related Formula $$\text{Steric Number} = \frac{7 + 3}{2} = 5 \quad (sp^3d \text{ hybridization})$$ ### Core Logic For $ClF_3$: Central atom Cl has 7 valence electrons. 3 bond pairs + 2 lone pairs = 5 electron pairs. Geometry based on trigonal bipyramidal arrangement gives a bent T-shape due to two equatorial lone pairs. ### Step 1: Conclusion Statement (2) is correct. ### Pattern Recognition $AX_3E_2$ molecules always exhibit a bent T-shaped geometry. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 11 Chemistry: Chemical Bonding and Molecular Structure

Q69 (2024)

Match List I with List II: <div style="overflow-x: auto; margin: 1rem 0;"><table style="width: 100%; border-collapse: collapse; text-align: left; font-size: 14px;"><thead><tr><th style="border: 1px solid #888; padding: 8px;">List I (Molecule)</th><th style="border: 1px solid #888; padding: 8px;">List II (Bonding description)</th></tr></thead><tbody><tr><td style="border: 1px solid #888; padding: 8px;">A. $C_2H_4$</td><td style="border: 1px solid #888; padding: 8px;">I. 3 $\sigma$ bonds, 2 $\pi$ bonds</td></tr><tr><td style="border: 1px solid #888; padding: 8px;">B. $C_2H_2$</td><td style="border: 1px solid #888; padding: 8px;">II. 3 $\sigma$ bonds, one lone pair</td></tr><tr><td style="border: 1px solid #888; padding: 8px;">C. $CH_4$</td><td style="border: 1px solid #888; padding: 8px;">III. 4 $\sigma$ bonds</td></tr><tr><td style="border: 1px solid #888; padding: 8px;">D. $NH_3$</td><td style="border: 1px solid #888; padding: 8px;">IV. 5 $\sigma$ bonds, 1 $\pi$ bond</td></tr></tbody></table></div> Choose the correct answer from the options given below:
  1. (1) A-IV, B-I, C-III, D-II
  2. (2) A-III, B-IV, C-II, D-I
  3. (3) A-I, B-II, C-IV, D-III
  4. (4) A-II, B-III, C-I, D-IV
### Related Formula $$\text{Single bond} = 1\sigma, \quad \text{Double bond} = 1\sigma + 1\pi, \quad \text{Triple bond} = 1\sigma + 2\pi$$ ### Core Logic A. $C_2H_4 \rightarrow 5\sigma$ bonds, $1\pi$ bond (IV). B. $C_2H_2 \rightarrow 3\sigma$ bonds, $2\pi$ bonds (I). C. $CH_4 \rightarrow 4\sigma$ bonds (III). D. $NH_3 \rightarrow 3\sigma$ bonds, 1 lone pair (II). ### Step 1: Conclusion Matches: A-IV, B-I, C-III, D-II. ### Pattern Recognition Count sigma, pi bonds, and lone pairs for simple hydrocarbons and ammonia. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 11 Chemistry: Chemical Bonding and Molecular Structure

Q86 (2024)

The correct formal charges on oxygen atoms numbered 2, 1 and 3 respectively are: {{IMG1}}
  1. (1) -1, 0, +1
  2. (2) 0, +1, -1
  3. (3) 0, 0, 0
  4. (4) +1, 0, -1
### Related Formula $$\text{Formal Charge} = V - L - \frac{S}{2}$$ ### Core Logic For Oxygen 2 (double bonded terminal): $FC = 6 - 4 - \frac{4}{2} = 0$. For Oxygen 1 (central atom): $FC = 6 - 2 - \frac{6}{2} = +1$. For Oxygen 3 (single bonded terminal): $FC = 6 - 6 - \frac{2}{2} = -1$. ### Step 1: Conclusion Formal charges on 2, 1, 3 are 0, +1, -1 respectively. ### Pattern Recognition Standard Lewis structure of ozone: central oxygen = +1, single-bonded terminal = -1, double-bonded terminal = 0. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 11 Chemistry: Chemical Bonding and Molecular Structure
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JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%) | JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%)

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