NEET · Chemistry —

Chemical Bonding and Molecular Structure appeared 3 times across 1 year — 6.7% of Chemistry. This question is from VSEPR Theory and Molecular Geometry.

Year 2024 Total
Questions 3 3
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Identify the correct statement about ClF₃ from the following options:

Solution & Explanation

Related Formula
Steric Number = (7 + 3)/(2) = 5 (sp³d hybridization)
Core Logic

For ClF₃: Central atom Cl has 7 valence electrons. 3 bond pairs + 2 lone pairs = 5 electron pairs. Geometry based on trigonal bipyramidal arrangement gives a bent T-shape due to two equatorial lone pairs.

Step 1: Conclusion

Statement (2) is correct.

Pattern Recognition

AX₃E₂ molecules always exhibit a bent T-shaped geometry.

Chapter Mix

Class 11 Chemistry: Chemical Bonding and Molecular Structure

Molecular structure of ClF3
Molecular structure of ClF3

Reference Study Guides

Chemical Bonding And Molecular Structure

More Chemical Bonding and Molecular Structure Previous-Year Questions

Q69 neet_2024_05_may_morning Covalent Bonds and Lone Pairs
Match List I with List II:
List I (Molecule)List II (Bonding description)
A. C₂H₄I. 3 σ bonds, 2 π bonds
B. C₂H₂II. 3 σ bonds, one lone pair
C. CH₄III. 4 σ bonds
D. NH₃IV. 5 σ bonds, 1 π bond
Choose the correct answer from the options given below:
  • A. (1) A-IV, B-I, C-III, D-II
  • B. (2) A-III, B-IV, C-II, D-I
  • C. (3) A-I, B-II, C-IV, D-III
  • D. (4) A-II, B-III, C-I, D-IV

Solution

Related Formula
Single bond = 1σ, Double bond = 1σ + 1π, Triple bond = 1σ + 2π
Core Logic

A. C₂H₄ arrow 5σ bonds, 1π bond (IV). B. C₂H₂ arrow 3σ bonds, 2π bonds (I). C. CH₄ arrow 4σ bonds (III). D. NH₃ arrow 3σ bonds, 1 lone pair (II).

Step 1: Conclusion

Matches: A-IV, B-I, C-III, D-II.

Pattern Recognition

Count sigma, pi bonds, and lone pairs for simple hydrocarbons and ammonia.

Chapter Mix

Class 11 Chemistry: Chemical Bonding and Molecular Structure

Q86 neet_2024_05_may_morning Formal Charge Calculations
The correct formal charges on oxygen atoms numbered 2, 1 and 3 respectively are:
Ozone molecule oxygen atoms numbered diagram for Q86 - JEE Main 2026 Morning
Lewis structure of ozone with numbered oxygen atoms 1, 2, and 3.
  • A. (1) -1, 0, +1
  • B. (2) 0, +1, -1
  • C. (3) 0, 0, 0
  • D. (4) +1, 0, -1

Solution

Related Formula
Formal Charge = V - L - (S)/(2)
Core Logic

For Oxygen 2 (double bonded terminal): FC = 6 - 4 - (4)/(2) = 0. For Oxygen 1 (central atom): FC = 6 - 2 - (6)/(2) = +1. For Oxygen 3 (single bonded terminal): FC = 6 - 6 - (2)/(2) = -1.

Step 1: Conclusion

Formal charges on 2, 1, 3 are 0, +1, -1 respectively.

Pattern Recognition

Standard Lewis structure of ozone: central oxygen = +1, single-bonded terminal = -1, double-bonded terminal = 0.

Chapter Mix

Class 11 Chemistry: Chemical Bonding and Molecular Structure

More Chemical Bonding and Molecular Structure Questions — neet_2024_05_may_morning

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JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%) | JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%)