Solution
Related Formula
R-OH + PCl₅ arrow R-Cl + POCl₃ + HCl CH₃-CH=CH₂ + HBr Peroxide CH₃CH₂CH₂BrCore Logic
- Propan-1-ol + PCl₅ arrow CH₃CH₂CH₂Cl + POCl₃ + HCl X = POCl₃.
- Dehydrohalogenation with alc. KOH yields propene (Y = CH₃CH=CH₂).
- Anti-Markovnikov addition of HBr in presence of peroxide (CH₃COO)₂ yields 1-bromopropane (Z = CH₃CH₂CH₂Br).
Step 1: Final Identification
X = POCl₃ and Z = CH₃CH₂CH₂Br.
Pattern Recognition
PCl₅ gives POCl₃ side product (whereas PCl₃ gives H₃PO₃). Peroxide + HBr guarantees terminal addition.
Chapter Mix
Class 12 Chemistry: Alcohols, Phenols and Ethers