Alcohols, Phenols and Ethers Previous Year Questions — NEET Chemistry

3 past-year Alcohols, Phenols and Ethers questions from NEET (Chemistry).

Q46 (2024)

Match List I with List II <div style="overflow-x: auto; margin: 1rem 0;"><table style="width: 100%; border-collapse: collapse; text-align: left; font-size: 14px;"><thead><tr><th style="border: 1px solid #888; padding: 8px;">List-I</th><th style="border: 1px solid #888; padding: 8px;">List-II</th></tr></thead><tbody><tr><td style="border: 1px solid #888; padding: 8px;">A. $H_3C-CH(OH)-CH_3$</td><td style="border: 1px solid #888; padding: 8px;">(I) (i) Oleum; (ii) $NaOH, \Delta$; (iii) $H^+$</td></tr><tr><td style="border: 1px solid #888; padding: 8px;">B. $CH_3COOH \rightarrow CH_3CH_2OH$</td><td style="border: 1px solid #888; padding: 8px;">(II) (i) $O_2$; (ii) $H_2O/H^+$</td></tr><tr><td style="border: 1px solid #888; padding: 8px;">C. $CH_3CH_2CH_2OH \rightarrow CH_3CH(OH)CH_3$</td><td style="border: 1px solid #888; padding: 8px;">(III) (i) $CH_3OH, H^+$; (ii) $H_2$, catalyst</td></tr><tr><td style="border: 1px solid #888; padding: 8px;">D. Cumene to Phenol</td><td style="border: 1px solid #888; padding: 8px;">(IV) (i) conc. $H_2SO_4, \Delta$; (ii) $H^+/H_2O$</td></tr></tbody></table></div> Choose the correct answer from the options given below:
  1. (1) A-I, B-III, C-IV, D-II
  2. (2) A-II, B-IV, C-III, D-I
  3. (3) A-II, B-III, C-I, D-IV
  4. (4) A-II, B-III, C-IV, D-II
### Related Formula $$\text{Cumene} + O_2 \rightarrow \text{Cumene hydroperoxide} \xrightarrow{H^+/H_2O} \text{Phenol} + \text{Acetone}$$ ### Core Logic A. Cumene hydroperoxide process gives Isopropanol/Phenol conversions (II). B. Reduction of carboxylic acid via esterification followed by catalytic reduction (III). C. Dehydration followed by hydration (IV). D. Phenol synthesis from benzene via oleum/sulfonation (I). ### Step 1: Conversion Breakdown Matching each reaction pair gives A-II, B-III, C-IV, D-I. ### Pattern Recognition Identify key named reactions: Cumene oxidation gives phenol + acetone; Acid reduction requires esterification intermediate. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Chemistry: Alcohols, Phenols and Ethers

Q52 (2024)

In the following reaction sequence, X and Z respectively are: {{IMG1}}
  1. (1) $X = POCl_3; Z = CH_3-CH(Br)-CH_3$
  2. (2) $X = H_3PO_3; Z = CH_3CH_2CH_2-Br$
  3. (3) $X = H_3PO_3; Z = CH_3-CH(Br)-CH_3$
  4. (4) $X = POCl_3; Z = CH_3CH_2CH_2-Br$
### Related Formula $$R-OH + PCl_5 \rightarrow R-Cl + POCl_3 + HCl$$ $$CH_3-CH=CH_2 + HBr \xrightarrow{\text{Peroxide}} CH_3CH_2CH_2Br$$ ### Core Logic 1. Propan-1-ol + $PCl_5 \rightarrow CH_3CH_2CH_2Cl + POCl_3 + HCl \implies X = POCl_3$. 2. Dehydrohalogenation with alc. $KOH$ yields propene ($Y = CH_3CH=CH_2$). 3. Anti-Markovnikov addition of $HBr$ in presence of peroxide $(CH_3COO)_2$ yields 1-bromopropane ($Z = CH_3CH_2CH_2Br$). ### Step 1: Final Identification $X = POCl_3$ and $Z = CH_3CH_2CH_2Br$. ### Pattern Recognition $PCl_5$ gives $POCl_3$ side product (whereas $PCl_3$ gives $H_3PO_3$). Peroxide + $HBr$ guarantees terminal addition. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Chemistry: Alcohols, Phenols and Ethers

Q74 (2024)

The functional group that can be identified through phthalein dye test is:
  1. (1) Phenolic
  2. (2) Alcohol
  3. (3) Aldehyde
  4. (4) Carboxylic acid
### Related Formula $$\text{Phenol} + \text{Phthalic anhydride} \xrightarrow{\text{conc. } H_2SO_4} \text{Phenolphthalein} \xrightarrow{NaOH} \text{Pink colour}$$ ### Core Logic Phthalein dye test is specific for phenolic $-OH$ groups. Phenol condenses with phthalic anhydride in presence of conc. $H_2SO_4$ to form phenolphthalein, giving pink colour in alkali. ### Step 1: Conclusion Functional group identified is Phenolic. ### Pattern Recognition Phthalein dye test $\rightarrow$ Specific qualitative test for Phenols. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Chemistry: Alcohols, Phenols and Ethers
Rankbit System
JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%) | JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%)

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