NEET · Chemistry —

Alcohols, Phenols and Ethers appeared 3 times across 1 year — 6.7% of Chemistry. This question is from Tests for Phenolic Group.

Year 2024 Total
Questions 3 3

The functional group that can be identified through phthalein dye test is:

Solution & Explanation

Related Formula
Phenol + Phthalic anhydride conc. H₂SO₄ Phenolphthalein NaOH Pink colour
Core Logic

Phthalein dye test is specific for phenolic -OH groups. Phenol condenses with phthalic anhydride in presence of conc. H₂SO₄ to form phenolphthalein, giving pink colour in alkali.

Step 1: Conclusion

Functional group identified is Phenolic.

Pattern Recognition

Phthalein dye test arrow Specific qualitative test for Phenols.

Chapter Mix

Class 12 Chemistry: Alcohols, Phenols and Ethers

Reference Study Guides

More Alcohols, Phenols and Ethers Previous-Year Questions

Q46 neet_2024_05_may_morning Chemical Reactions and Conversions
Match List I with List II
List-IList-II
A. H₃C-CH(OH)-CH₃(I) (i) Oleum; (ii) NaOH, Δ; (iii) H^+
B. CH₃COOH arrow CH₃CH₂OH(II) (i) O₂; (ii) H₂O/H^+
C. CH₃CH₂CH₂OH arrow CH₃CH(OH)CH₃(III) (i) CH₃OH, H^+; (ii) H₂, catalyst
D. Cumene to Phenol(IV) (i) conc. H₂SO₄, Δ; (ii) H^+/H₂O
Choose the correct answer from the options given below:
Chemical Reactions diagram for Q46 - JEE Main 2026 Morning
Reagent mapping for functional group conversions in organic chemistry.
Chemical Reactions diagram for Q46 - JEE Main 2026 Morning
Reagent mapping for functional group conversions in organic chemistry.
Chemical Reactions diagram for Q46 - JEE Main 2026 Morning
Reagent mapping for functional group conversions in organic chemistry.
  • A. (1) A-I, B-III, C-IV, D-II
  • B. (2) A-II, B-IV, C-III, D-I
  • C. (3) A-II, B-III, C-I, D-IV
  • D. (4) A-II, B-III, C-IV, D-II

Solution

Related Formula
Cumene + O₂ arrow Cumene hydroperoxide H^+/H₂O Phenol + Acetone
Core Logic

A. Cumene hydroperoxide process gives Isopropanol/Phenol conversions (II).

B. Reduction of carboxylic acid via esterification followed by catalytic reduction (III).

C. Dehydration followed by hydration (IV).

D. Phenol synthesis from benzene via oleum/sulfonation (I).

Step 1: Conversion Breakdown

Matching each reaction pair gives A-II, B-III, C-IV, D-I.

Pattern Recognition

Identify key named reactions: Cumene oxidation gives phenol + acetone; Acid reduction requires esterification intermediate.

Chapter Mix

Class 12 Chemistry: Alcohols, Phenols and Ethers

Q52 neet_2024_05_may_morning Reaction Sequences of Alcohols
In the following reaction sequence, X and Z respectively are:
Reaction sequence diagram for Q52 - JEE Main 2026 Morning
Multistep reaction sequence starting from propan-1-ol with PCl5 and peroxide addition.
  • A. (1) X = POCl₃; Z = CH₃-CH(Br)-CH₃
  • B. (2) X = H₃PO₃; Z = CH₃CH₂CH₂-Br
  • C. (3) X = H₃PO₃; Z = CH₃-CH(Br)-CH₃
  • D. (4) X = POCl₃; Z = CH₃CH₂CH₂-Br

Solution

Related Formula
R-OH + PCl₅ arrow R-Cl + POCl₃ + HCl CH₃-CH=CH₂ + HBr Peroxide CH₃CH₂CH₂Br
Core Logic
  • Propan-1-ol + PCl₅ arrow CH₃CH₂CH₂Cl + POCl₃ + HCl X = POCl₃.
  • Dehydrohalogenation with alc. KOH yields propene (Y = CH₃CH=CH₂).
  • Anti-Markovnikov addition of HBr in presence of peroxide (CH₃COO)₂ yields 1-bromopropane (Z = CH₃CH₂CH₂Br).
Step 1: Final Identification

X = POCl₃ and Z = CH₃CH₂CH₂Br.

Pattern Recognition

PCl₅ gives POCl₃ side product (whereas PCl₃ gives H₃PO₃). Peroxide + HBr guarantees terminal addition.

Chapter Mix

Class 12 Chemistry: Alcohols, Phenols and Ethers

More Alcohols, Phenols and Ethers Questions — neet_2024_05_may_morning

Practice all Alcohols, Phenols and Ethers previous-year questions →

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