Q14
neet_2026_03_may_morning
Newton's Second Law of Motion
The magnitude and direction of the acceleration produced in a body of mass 5 ~kg when two mutually perpendicular forces 8 ~N and 6 ~N act on it, are respectively:
Solution
Related Formula
Fₙₑₜ = √(F₁² + F₂²) a = Fₙₑₜm θ = (Fy)/(Fₓ)Core Logic
Since the two forces 6 ~N and 8 ~N are mutually perpendicular, their resultant force magnitude is:
Fₙₑₜ = √(6² + 8²) = √(36 + 64) = √(100) = 10 ~NThe acceleration produced is:
a = (10)/(5) = 2 ~m/s²Step 1: Find Direction
To find the angle θ from the 8 ~N force:
θ = (6)/(8) = (3)/(4) θ = ⁻¹((3)/(4)) from the 8 ~N force.Pattern Recognition
A classic 3-4-5 force triangle. 6N and 8N give 10N resultant. Angle with the 8N vector is derived using θ = OppositeAdjacent = (6)/(8) = (3)/(4).
Chapter Mix
Class 11 Physics: Laws of Motion
