The number of chlorine atoms present in the organic products X and Y of the following reactions, respectively, are:

Related Formula

Core Logic

Reaction 1: Benzene + 6Cl₂$6Cl_2$ in presence of anhyd. AlCl₃$AlCl_3$ (dark, cold) gives Hexachlorobenzene (X = C₆Cl₆$X = C_6Cl_6$), having 6 chlorine atoms.

Reaction 2: Benzene + 3Cl₂$3Cl_2$ in presence of UV light at 500 K gives Benzene Hexachloride (Y = C₆H₆Cl₆$Y = C_6H_6Cl_6$), also having 6 chlorine atoms.

Step 1: Conclusion

Number of chlorine atoms in X and Y are 6 and 6 respectively.

Pattern Recognition

Both exhaustive substitution (C₆Cl₆$C_6Cl_6$) and addition (C₆H₆Cl₆$C_6H_6Cl_6$) produce compounds containing 6 chlorine atoms.

Chapter Mix

Class 12 Chemistry: Haloalkanes and Haloarenes