Q51 (2024)
The number of chlorine atoms present in the organic products X and Y of the following reactions, respectively, are:
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- (1) 3 and 6
- (2) 6 and 6
- (3) 6 and 3
- (4) 3 and 3
### Related Formula
$$\text{Benzene} + 6Cl_2 \xrightarrow[\text{dark, cold}]{\text{Anhyd. } AlCl_3} C_6Cl_6 + 6HCl$$
$$\text{Benzene} + 3Cl_2 \xrightarrow[500 \text{ K}]{UV} C_6H_6Cl_6$$
### Core Logic
Reaction 1: Benzene + $6Cl_2$ in presence of anhyd. $AlCl_3$ (dark, cold) gives Hexachlorobenzene ($X = C_6Cl_6$), having 6 chlorine atoms.
Reaction 2: Benzene + $3Cl_2$ in presence of UV light at 500 K gives Benzene Hexachloride ($Y = C_6H_6Cl_6$), also having 6 chlorine atoms.
### Step 1: Conclusion
Number of chlorine atoms in X and Y are 6 and 6 respectively.
### Pattern Recognition
Both exhaustive substitution ($C_6Cl_6$) and addition ($C_6H_6Cl_6$) produce compounds containing 6 chlorine atoms.
### Evaluation Rubric / Model Answer
null
### Chapter Mix
Class 12 Chemistry: Haloalkanes and Haloarenes
