Given below are two statements: Statement (I): is more polar than . Statement (II): Boiling point of is lower than the ortho-isomer, but it is more polar than the meta-isomer. In the light of the above statements, choose the most appropriate answer from the options given below:

Let's analyze the visual structures alongside their scientific orientations: - Statement (I) compares 1,2-dichlorobenzene and 1,2-dibromobenzene. Chlorine has a higher electronegativity than bromine, creating a larger bond dipole. The vacant d-orbital interactions do not invert this baseline dipole trend. Thus, 1,2-dichlorobenzene is more polar, making Statement I correct. - Statement (II) evaluates dihalobenzene isomers. For the para-isomer, individual bond dipoles are oriented at 180, cancelling out completely: Since mumeta > 0, the para-isomer is *less* polar than the meta-isomer. This directly falsifies Statement II. The geometric configurations map out as follows: Hence, Statement I is correct, but Statement II is incorrect. Dipole tracking rule: Para-substituted benzenes with identical groups possess a structural center of inversion, guaranteeing a net dipole moment of exactly zero (mu = 0). They can never be more polar than any asymmetric ortho or meta structural isomer. Class 12 Chemistry: Haloalkanes and Haloarenes

Given below are two statements: Statement (I): is more polar than . Statement (II): Boiling point of is lower than the ortho-isomer, but it is more polar than the meta-isomer. In the light of the abov

Let's analyze the visual structures alongside their scientific orientations: - Statement (I) compares 1,2-dichlorobenzene and 1,2-dibromobenzene. Chlorine has a higher electronegativity than bromine, creating a larger bond dipole. The vacant d-orbital interactions do not invert this baseline dipole trend. Thus, 1,2-dichlorobenzene is more polar, making Statement I correct. - Statement (II) evaluates dihalobenzene isomers. For the para-isomer, individual bond dipoles are oriented at 180, cancelli

Given below are two statements: Statement (I): is more polar than . Statement (II): Boiling point of is lower than the ortho-isomer, but it is more polar than the meta-isomer. In the light of the above statements, choose the most appropriate answer from the options given below:

Let's analyze the visual structures alongside their scientific orientations: - Statement (I) compares 1,2-dichlorobenzene and 1,2-dibromobenzene. Chlorine has a higher electronegativity than bromine, creating a larger bond dipole. The vacant d-orbital interactions do not invert this baseline dipole trend. Thus, 1,2-dichlorobenzene is more polar, making Statement I correct. - Statement (II) evaluates dihalobenzene isomers. For the para-isomer, individual bond dipoles are oriented at 180, cancelling out completely: Since mumeta > 0, the para-isomer is *less* polar than the meta-isomer. This directly falsifies Statement II. The geometric configurations map out as follows: Hence, Statement I is correct, but Statement II is incorrect. Dipole tracking rule: Para-substituted benzenes with identical groups possess a structural center of inversion, guaranteeing a net dipole moment of exactly zero (mu = 0). They can never be more polar than any asymmetric ortho or meta structural isomer. Class 12 Chemistry: Haloalkanes and Haloarenes

Given below are two statements: Statement (I): is more polar than . Statement (II): Boiling point of is lower than the ortho-isomer, but it is more polar than the meta-isomer. In the light of the abov

Let's analyze the visual structures alongside their scientific orientations: - Statement (I) compares 1,2-dichlorobenzene and 1,2-dibromobenzene. Chlorine has a higher electronegativity than bromine, creating a larger bond dipole. The vacant d-orbital interactions do not invert this baseline dipole trend. Thus, 1,2-dichlorobenzene is more polar, making Statement I correct. - Statement (II) evaluates dihalobenzene isomers. For the para-isomer, individual bond dipoles are oriented at 180, cancelli

Given below are two statements: Statement (I): is more polar than . Statement (II): Boiling point of is lower than the…

Year	2026	2025	2024	Total
Questions	11	16	13	40

Q54 jee_main_2026_21_jan_morning Reactions of Haloalkanes

A hydrocarbon ‘P’ (

C₄H₈

) on reaction with HCl gives an optically active compound ‘Q’ (

C₄H₉Cl

) which on reaction with one mole of ammonia gives compound ‘R’ (

C₄H₁₁N

). ‘R’ on diazotization followed by hydrolysis gives ‘S’. Identify P, Q, R and S.

A. $P = CH₃ - CH₂ - CH = CH₂, Q = CH₃ - CH₂ - CH₂ - CH₂Cl, R = CH₃ - CH₂ - CH₂ - NH₂, S = CH₃ - CH₂ - CH(OH) - CH₃$
B. $P = Cyclobutane, Q = 1-Chlorobutane, R = Butan-1-amine, S = Cyclobutanol$
C. $P = CH₃ - CH = CH - CH₃, Q = CH₃ - CH₂ - CH(Cl) - CH₃, R = CH₃ - CH₂ - CH(NH₂) - CH₃, S = CH₃ - CH₂ - CH(OH) - CH₃$
D. $P = CH₃ - CH = CH - CH₃, Q = CH₃ - CH₂ - CH₂ - CH₂ - Cl, R = CH₃ - CH₂ - CH₂ - CH₂ - NH₂, S = CH₃ - CH₂ - CH₂ - CH₂ - OH$

Solution

Core Logic

Since P ( $C₄H₈$ $C_4H_8$) reacts with HCl to give an optically active compound Q ( $C₄H₉Cl$ $C_4H_9Cl$), P must be But-2-ene. Addition of HCl yields 2-chlorobutane, which possesses a chiral center.

CH₃-CH=CH-CH₃ HCl CH₃-CH₂-C^*H(Cl)-CH₃ (P is But-2-ene, Q is 2-chlorobutane)

Reactions of Haloalkanes diagram for Q54 - JEE Main 2026 Morning

Compound Q reacts with $NH₃$ $\mathrm{NH}_3$ to undergo nucleophilic substitution forming a primary amine R:

CH₃-CH₂-CH(Cl)-CH₃ NH₃ CH₃-CH₂-CH(NH₂)-CH₃ (R is Butan-2-amine)

Diazotization of primary aliphatic amines followed by hydrolysis yields an alcohol via a carbocation intermediate (S):

CH₃-CH₂-CH(NH₂)-CH₃ NaNO₂ / HCl / H₂O CH₃-CH₂-CH(OH)-CH₃ (S is Butan-2-ol)

Pattern Recognition

An optically active alkyl halide formed from a $C₄H₈$ $C_4H_8$ alkene with HX is a classic pointer to 2-halobutane originating from But-2-ene or But-1-ene. Diazotization of primary aliphatic amines ( $R-NH₂$ $R-NH_2$) with $NaNO₂/HCl$ $NaNO_2/HCl$ yields alcohols ( $R-OH$ $R-OH$) with possible rearrangements, though here a secondary carbocation is already stable.

Chapter Mix

Class 12 Chemistry: Haloalkanes and Haloarenes Class 12 Chemistry: Amines

Q59 jee_main_2026_21_jan_evening Nucleophilic Substitution ($S_N1$) and Carbocation Stability

The correct order of reactivity of the following benzyl halides towards reaction with

KCN

is:

Benzyl halide structures for Q59 - JEE Main 2026 Evening — Four substituted benzyl halide structures labelled a, b, c, d.

A. $(1) a > b > c > d$ $(1) \ a > b > c > d$
B. $(2) b > a > d > c$ $(2) \ b > a > d > c$
C. $(3) b > a > c > d$ $(3) \ b > a > c > d$
D. $(4) a > b > d > d$ $(4) \ a > b > d > d$