Solution
Related Formula
k = 0.693t1/2 t = (2.303)/(k) ( (a)/(a - x) )Core Logic
Since r = k[A], the reaction follows first-order kinetics. The half-life (50% decomposition) is t1/2 = 120 minutes.
Step 1: Calculating for 90% decomposition
For 90% completion of the reaction, [A]₀ = 100 and [A]ₜ = 100 - 90 = 10.
t = (2.303)/(k) (100)/(10) t = 2.303( 0.693t1/2 ) (10) t = (2.303 × 120)/(0.693) × 1 t = 398.78 minutesRounding off to the nearest integer, we get 399 minutes.
Pattern Recognition
For a first order reaction, t90% ≈ 3.32 × t50%. 120 × 3.32 = 398.4, so roughly 399.
Chapter Mix
Class 12 Chemistry: Chemical Kinetics