NEET · Physics —

Gravitation appeared 1 time across 1 year — 2.2% of Physics. This question is from Gravitational Potential Energy.

Year 2024 Total
Questions 1 1

The amount of work done to raise a mass 'm' from the surface of the Earth to a height equal to the radius of the Earth 'R' will be

Solution & Explanation

Related Formula
Δ U = Uf - Uᵢ U = -(GMm)/(r) g = (GM)/(R²)
Core Logic

The work done by an external force is equal to the change in gravitational potential energy.

Initial Potential Energy (at surface, r = R):

U₁ = -(GMm)/(R)

Final Potential Energy (at height h = R, distance from center r = 2R):

U₂ = -(GMm)/(R + R) = -(GMm)/(2R)
Step 1: Calculate Work Done
W.D. = U₂ - U₁ W.D. = -(GMm)/(2R) - (-(GMm)/(R)) W.D. = -(GMm)/(2R) + (GMm)/(R) = (GMm)/(2R)

Substitute GM = gR²:

W.D. = ((gR²)m)/(2R) = (mgR)/(2)
Pattern Recognition

Standard shortcut formula for work done against gravity to height h: W = (mgh)/(1 + h/R). Plugging h = R yields (mgR)/(1 + 1) = (mgR)/(2) instantly.

Chapter Mix

Class 11 Physics: Gravitation Class 11 Physics: Work Energy and Power

Reference Study Guides

More Gravitation Questions — neet_2026_03_may_morning

Practice all Gravitation previous-year questions →

Rankbit System
JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%) | JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%)