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Chemical Bonding and Molecular Structure appeared 42 times across 3 years — 4.9% of Chemistry. This question is from VSEPR Theory And Molecular Geometry.

Year 2026 2025 2024 Total
Questions 12 14 16 42

Match List-I with List-II according to shape.
List-IList-II
(A) XeO₃(I) BrF₅
(B) XeF₂(II) NH₃
(C) XeO₂F₂(III) [I₃]⁻
(D) XeOF₄(IV) SF₄
Choose the correct answer from the options given below:

Solution & Explanation

Core Logic

Evaluate steric number (SN) = Bond Pairs (BP) + Lone Pairs (LP): (A) XeO₃: 3 BP, 1 LP arrow Pyramidal geometry. Matches NH₃ (3 BP, 1 LP). (B) XeF₂: 2 BP, 3 LP arrow Linear geometry. Matches [I₃]^- (2 BP, 3 LP). (C) XeO₂F₂: 4 BP, 1 LP arrow See-saw geometry. Matches SF₄ (4 BP, 1 LP). (D) XeOF₄: 5 BP, 1 LP arrow Square pyramidal geometry. Matches BrF₅ (5 BP, 1 LP).

Step 1: Final Conclusion

Matching pairs: A-II, B-III, C-IV, D-I.

Pattern Recognition

VSEPR iso-structural matching. Always count valence electrons of central atom minus bonds to find lone pairs. 4 domains with 1 LP = See-saw. 5 domains with 3 LP = Linear. 4 domains with 1 LP (sp3) = Pyramidal.

Chapter Mix

Class 11 Chemistry: Chemical Bonding and Molecular Structure Class 12 Chemistry: The p-Block Elements

Reference Study Guides

More Chemical Bonding and Molecular Structure Previous-Year Questions — Page 9

Q77 jee_main_2024_31_jan_morning Molecular Orbital Theory
The linear combination of atomic orbitals to form molecular orbitals takes place only when the combining atomic orbitals A. have the same energy B. have the minimum overlap C. have same symmetry about the molecular axis D. have different symmetry about the molecular axis Choose the most appropriate from the options given below:
  • A. A, B, C only
  • B. A and C only
  • C. B, C, D only
  • D. B and D only

Solution

Core Logic

Conditions for the linear combination of atomic orbitals (LCAO) to form molecular orbitals:

  • The combining atomic orbitals must have the same or nearly the same energy.
  • The combining atomic orbitals must have the same symmetry about the molecular axis.
  • The combining atomic orbitals must overlap to the maximum extent (not minimum).
Chapter Mix

Class 11 Chemistry: Chemical Bonding and Molecular Structure

Q85 jee_main_2024_31_jan_morning Hybridization
The number of species from the following in which the central atom uses sp³ hybrid orbitals in its bonding is NH₃, SO₂, SiO₂, BeCl₂, CO₂, H₂O, CH₄, BF₃
Numerical Answer. Answer: 4 to 4

Solution

Core Logic

Analyzing the hybridization of the central atom in each species:

  • NH₃: 3 bp + 1 lp = 4 electron domains arrow sp³
  • SO₂: 2 bp + 1 lp = 3 electron domains arrow sp²
  • SiO₂: A giant covalent network where each Si is bonded to 4 oxygens tetrahedrally arrow sp³
  • BeCl₂: 2 bp + 0 lp = 2 electron domains arrow sp
  • CO₂: 2 bp + 0 lp = 2 electron domains arrow sp
  • H₂O: 2 bp + 2 lp = 4 electron domains arrow sp³
  • CH₄: 4 bp + 0 lp = 4 electron domains arrow sp³
  • BF₃: 3 bp + 0 lp = 3 electron domains arrow sp²
  • Total species with sp³ hybridization: NH₃, SiO₂, H₂O, CH₄. Total count = 4.

Chapter Mix

Class 11 Chemistry: Chemical Bonding and Molecular Structure

More Chemical Bonding and Molecular Structure Questions — jee_main_2026_28_january_evening

Practice all Chemical Bonding and Molecular Structure previous-year questions →

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JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%) | JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%)