Two identical symmetric double convex lenses of focal length f are cut into two equal parts L_1, L_2 by AB plane and L_3, L_4 by XY plane as shown in figure respectively. The ratio of focal lengths of lenses L_1 and L_3 is:
Cutting of Lenses diagram for Q7 - JEE Main 2025 Evening
The figure details a convex lens being cut along the horizontal plane AB and vertical plane XY to create components L1, L2, L3, and L4.

Solution & Explanation

### Related Formula frac1f = (mu - 1)left(frac1R_1 - frac1R_2right) ### Core Logic 1. **Cutting along horizontal plane AB**: When a lens is cut along its principal axis, the radius of curvature of neither surface changes. Thus, the focal length of the split parts L_1 and L_2 remains exactly equal to the initial focal length: f_L_1 = f 2. **Cutting along vertical plane XY**: When a lens is cut perpendicular to the principal axis into two symmetric plano-convex lenses, one surface becomes flat (R_2 = infty). According to Lens Maker's Formula, the focal length of parts L_3 and L_4 doubles: f_L_3 = 2f 3. **Ratio Determination**: fracf_L_1f_L_3 = fracf2f = frac12 Hence, the ratio is 1:2. ### Pattern Recognition Shortcut rule for lens cutting: - Horizontal cut (along axis) rightarrow Focal length stays f. - Vertical cut (perp to axis) rightarrow Focal length doubles to 2f. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Physics: Ray Optics and Optical Instruments

Reference Study Guides

More Ray Optics and Optical Instruments Previous-Year Questions — Page 10

Q34 jee_main_2024_31_jan_morning Prism Deviation
The refractive index of a prism with apex angle A is cot(A/2). The angle of minimum deviation is :
  • A. delta_mathrmm = 180^circ - A
  • B. delta_mathrmm = 180^circ - 3A
  • C. delta_mathrmm = 180^circ - 4A
  • D. delta_mathrmm = 180^circ - 2A

Solution

### Related Formula mu = fracsinleft(fracA + delta_m2right)sinleft(fracA2right) ### Core Logic Given that the refractive index mu = cotleft(fracA2right). Substituting this into the prism formula: cotleft(fracA2right) = fracsinleft(fracA + delta_m2right)sinleft(fracA2right) fraccosleft(fracA2right)sinleft(fracA2right) = fracsinleft(fracA + delta_m2right)sinleft(fracA2right) Equating the numerators: cosleft(fracA2right) = sinleft(fracA + delta_m2right) We can rewrite cosine in terms of sine: sinleft(fracpi2 - fracA2right) = sinleft(fracA + delta_m2right) ### Step 2: Solve for Deviation Comparing the angles inside the sine functions: fracpi2 - fracA2 = fracA2 + fracdelta_m2 Multiply the entire equation by 2: pi - A = A + delta_m delta_m = pi - 2A Converting radians to degrees: delta_m = 180^circ - 2A ### Pattern Recognition Whenever refractive index mu = cot(A/2), the relation sin(90^circ - A/2) strictly matches the prism sine equation, meaning minimum deviation delta_m is always 180^circ - 2A. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Physics: Ray Optics And Optical Instruments

More Ray Optics and Optical Instruments Questions — jee_main_2025_29_jan_evening

Practice all Ray Optics and Optical Instruments previous-year questions →

Rankbit System
JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%) | JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%)