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Structure of Atom appeared 38 times across 3 years — 4.4% of Chemistry. This question is from Bohr Model for Hydrogen-like Species.

Year 2026 2025 2024 Total
Questions 14 15 9 38

For hydrogen like species, which of the following graphs provides the most appropriate representation of E vs Z plot for a constant n? [E: Energy of the stationary state, Z: atomic number, n: principal quantum number]

Solution & Explanation

Related Formula
Eₙ = -13.6 (Z²)/(n²) eV
Core Logic

For a constant principal quantum number n, the energy E is directly proportional to -Z². This represents a quadratic relation where the curve is a downward-opening parabola starting from the origin in the negative energy region.

Pattern Recognition

Since energy values are inherently negative for bound states, as Z increases, E becomes rapidly more negative following a parabolic curve.

Chapter Mix

Class 11 Chemistry: Structure of Atom

Reference Study Guides

More Structure of Atom Previous-Year Questions — Page 5

Q40 jee_main_2025_29_jan_evening Heisenberg's Uncertainty Principle
Given below are two statements: Statement (I): It is impossible to specify simultaneously with arbitrary precision, both the linear momentum and the position of a particle. Statement (II) If the uncertainty in the measurement of position and uncertainty in measurement of momentum are equal for an electron, then the uncertainty in the measurement of velocity is gesqrt(h)/(pi)×(1)/(2m) In the light of the above statements, choose the correct answer from the options given below:
  • A. Statement I is true but Statement II is false.
  • B. Both Statement I and Statement II are true.
  • C. Statement I is false but Statement II is true.
  • D. Both Statement I and Statement II are false.

Solution

Related Formula
Delta x cdot Delta p ge (h)/(4pi)
Core Logic

Statement I is a verbatim definition of Heisenberg's Uncertainty Principle, hence it is completely true.

For Statement II, we are given that Delta x = Delta p:

Delta p cdot Delta p ge (h)/(4pi) implies (Delta p)² ge (h)/(4pi) Delta p ge sqrt(h)/(4pi) = (1)/(2)sqrt(h)/(pi)

Since Delta p = m cdot Delta v:

m cdot Delta v ge (1)/(2)sqrt(h)/(pi) implies Delta v ge (1)/(2m)sqrt(h)/(pi)

This perfectly matches Statement II, so it is also true.

Pattern Recognition

When solving inequality bounds for identical uncertainties, always substitute directly to obtain a clean quadratic form before taking the square root.

Chapter Mix

Class 11 Chemistry: Structure of Atom

Q38 jee_main_2025_28_jan_morning Quantum Numbers and Orbital Energies
In a multielectron atom, which of the following orbitals described by three quantum numbers with have same energy in absence of electric and magnetic fields? A. n = 1, l = 0, ml = 0 B. n = 2, l = 0, ml = 0 C. n = 2, l = 1, ml = 1 D. n = 3, l = 2, ml = 1 E. n = 3, l = 2, ml = 0 Choose the correct answer from the options given below:
  • A. A and B only
  • B. B and C only
  • C. C and D only
  • D. D and E only

Solution

Core Logic

In multi-electron systems, the energy profile depends on both the primary shell (n) and azimuthal subshell (l) quantum values via the (n+l) rule. Orbitals sharing the exact same n and l values are energy-degenerate as long as external field metrics are zero. Let us map each set:

  • A: 1s
  • B: 2s
  • C: 2p
  • D: 3d (ml = 1)
  • E: 3d (ml = 0)
  • Since both D and E describe subcomponents of the same 3d subshell (n=3, l=2), they share identical energies, establishing perfect degeneracy.

Pattern Recognition

Sees: Orbitals matching energy level in multi-electron space. Trap: Confusing single-electron hydrogen atoms (where energy depends solely on n) with multielectron atoms.

Chapter Mix

Class 11 Chemistry: Structure of Atom

Q38 jee_main_2025_04_april_evening Quantum Numbers and Electronic Configuration
Consider the ground state of chromium atom (Z = 24). How many electrons are with Azimuthal quantum number l = 1 and l = 2 respectively?
  • A. 12 and 4
  • B. 16 and 4
  • C. 12 and 5
  • D. 16 and 5

Solution

Related Formula
Azimuthal Quantum Number: l=1 p-orbital, l=2 d-orbital
Core Logic

The ground-state electronic configuration of Chromium (Z=24) is anomalous due to half-filled stability:

Cr: 1s² 2s² 2p⁶ 3s² 3p⁶ 3d⁵ 4s¹

Now count the electrons in specific subshells:

  • For l = 1 (p-electrons): present in 2p⁶ and 3p⁶ 6 + 6 = 12 electrons.
  • For l = 2 (d-electrons): present in 3d⁵ 5 electrons.
  • Thus, the counts are 12 and 5 respectively.

Pattern Recognition

Always remember the 3d⁵ 4s¹ exception for Chromium (Z=24) and 3d¹⁰ 4s¹ for Copper (Z=29). Forgetting the half-filled d-subshell exception will lead to the wrong answer (12 and 4).

Chapter Mix

Class 11 Chemistry: Structure of Atom

Q45 jee_main_2025_04_april_morning Quantum Mechanical Model of Atom
Which one of the following about an electron occupying the 1s orbital in a hydrogen atom is incorrect? (Bohr's radius is represented by a₀)
  • A. The probability density of finding the electron is maximum at the nucleus
  • B. The electron can be found at a distance 2a₀ from the nucleus
  • C. The 1s orbital is spherically symmetrical
  • D. The total energy of the electron is maximum when it is at a distance a₀ from the nucleus

Solution

Core Logic

Let's evaluate each statement using quantum mechanics:

  • Statement (1) is correct: The wave function squared Ψ² (probability density) for a 1s orbital peaks directly at the nucleus (r = 0).
  • Statement (2) is correct: The boundary distribution curves drop off exponentially but approach zero only at infinity, meaning the electron has a non-zero probability of being found at any distance, including 2a₀.
  • Statement (3) is correct: All s-orbitals have an angular wave function component of unity, making them perfectly spherical.
  • Statement (4) is incorrect: The total energy of a bound electron in a hydrogen atom is constant for a given principal quantum number quantum state (E = -13.6~eV when n=1), independent of its spatial distance from the nucleus.
Pattern Recognition

Total energy is a fixed state property defined strictly by the principal quantum number n. It never varies as a function of the electron's position coordinates within that orbital state.

Chapter Mix

Class 11 Chemistry: Structure of Atom

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JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%) | JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%)