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Mechanical Properties of Fluids appeared 31 times across 3 years — 3.6% of Physics. This question is from Surface Tension and Viscosity.

Year 2026 2025 2024 Total
Questions 9 14 8 31

Consider following statements: A. Surface tension arises due to extra energy of the molecules at the interior as compared to the molecules at the surface, of a liquid. B. As the temperature of liquid rises, the coefficient of viscosity increases. C. As the temperature of gas increases, the coefficient of viscosity increases. D. The onset of turbulence is determined by Reynold's number. E. In a steady flow two stream lines never intersect. Choose the correct answer from the options given below:

Solution & Explanation

Core Logic

Let's audit each fluid mechanics assertion:

Statement A: Incorrect. Surface tension arises because surface molecules possess higher potential energy compared to interior bulk molecules due to net cohesive forces pulling inward.

Statement B: Incorrect. With rising temperatures, cohesive forces in liquids weaken, causing viscosity to decrease.

Statement C: Correct. In gases, viscosity is governed by molecular collisions. Higher temperature leads to increased thermal activity and momentum exchange, increasing viscosity.

Statement D: Correct. Critical velocity and turbulence parameters are completely defined by the dimensionless Reynolds number.

Statement E: Correct. If streamlines intersected, a fluid particle at that spatial node would have two distinct velocity directions, violating steady-state constraints.

Step 1: Final Conclusion

Statements C, D, and E are correct, leading to option (2).

Pattern Recognition

Contrast Liquid vs Gas viscosity trends under temperature increments: Liquids down (intermolecular bounds weaken), Gases up (random thermal diffusion and collision rates escalate).

Chapter Mix

Class 11 Physics: Mechanical Properties of Fluids

Reference Study Guides

More Mechanical Properties of Fluids Previous-Year Questions

Q jee_main_2026_21_jan_morning Bernoulli's Principle
Water flows through a horizontal tube as shown in the figure. The difference in height between the water columns in vertical tubes is 5 cm and the area of cross-sections at A and B are 6 cm² and 3 cm² respectively. The rate of flow will be ____ cm³/s. (take g = 10 m/s²)
Bernoulli's Principle diagram for Q29 - JEE Main 2026 Morning
The figure illustrates a Venturi meter setup with water flowing through a variable cross-section tube.
  • A. 200√(3)
  • B. 200√(6)
  • C. 200√(3)
  • D. 100√(3)

Solution

Related Formula
A₁ V₁ = A₂ V₂ P₁ + (1)/(2)ρ V₁² = P₂ + (1)/(2)ρ V₂² P₁ - P₂ = ρ g h
Core Logic

From the continuity equation between A and B:

AAVA = ABVB 6VA = 3VB VB = 2VA

Applying Bernoulli's equation between A and B for a horizontal pipe:

PA + (1)/(2)ρ VA² = PB + (1)/(2)ρ VB² PA - PB = (1)/(2)ρ(VB² - VA²)

Since the height difference is h = 5 cm = 0.05 m, the pressure difference is ρ gh.

ρ g × 0.05 = (1)/(2)ρ( (2VA)² - VA² ) g × 0.05 = (1)/(2)(3VA²)
Step 1: Calculate Velocity and Volume Flow Rate

Solving for VA:

VA = √((2 × 10 × 0.05)/(3)) = √((1)/(3)) = 1√(3) m/s VA = 100√(3) cm/s

Volume flow rate Q = AA VA:

Q = 6 cm² × 100√(3) cm/s = 600√(3) = 200√(3) cm³/s
Pattern Recognition

In a horizontal Venturi meter, substituting V₂ = V₁ (A₁/A₂) directly into ρ g h = (1)/(2)ρ (V₂² - V₁²) is the standard path. Working in CGS vs MKS units requires careful tracking; convert VA to cm/s before multiplying by AA in cm².

Chapter Mix

Class 11 Physics: Mechanical Properties of Fluids

Q38 jee_main_2026_21_jan_evening Surface Tension
Surface tension of two liquids (having same densities), T₁ and T₂, are measured using capillary rise method utilizing two tubes with inner radii of r₁ and r₂ where r₁ > r₂. The measured liquid heights in these tubes are h₁ and h₂ respectively. [Ignore the weight of the liquid about the lowest point of miniscus]. The heights h₁ and h₂ and surface tensions T₁ and T₂ satisfy the relation :
  • A. h₁ < h₂ and T₁ = T₂
  • B. h₁ = h₂ and T₁ = T₂
  • C. h₁ > h₂ and T₁ = T₂
  • D. h₁ > h₂ and T₁ < T₂

Solution

Related Formula
h = (2T θ)/(ρ g r)
Core Logic

Since we are assessing surface tension T as a property of the liquids, the question intends to compare liquids that are identical (implying T₁ = T₂ and same density).

Capillary rise formula block for Q38 - JEE Main 2026 Evening
Capillary rise formula block for Q38 - JEE Main 2026 Evening
By Jurin's Law, for identical liquids, the height of capillary rise is inversely proportional to the radius of the tube:

h ∝ (1)/(r)
Step 1: Final Conclusion

Given r₁ > r₂, the inverse proportionality directly implies that the liquid will rise less in the wider tube. Therefore, h₁ < h₂ and naturally T₁ = T₂ for the intrinsic property.

Pattern Recognition

Wider tubes (r large) cause lower capillary rises (h small). h ∝ 1/r is a foundational inverse relationship in capillary action.

Chapter Mix

Class 11 Physics: Mechanical Properties of Fluids

Q47 jee_main_2026_21_jan_evening Terminal Velocity
The terminal velocity of a metallic ball of radius 6 mm in a viscous fluid is 20 cm/s. The terminal velocity of another ball of same material and having radius 3 mm in the same fluid will be ________ cm/s.
Numerical Answer. Answer: 5 to 5

Solution

Related Formula
vT = (2r² g)/(9η) (σ - ρ)
Core Logic

For balls of the same material falling through the same fluid, all terms in the terminal velocity equation except the radius r are constant. Therefore, vT ∝ r².

Step 1: Setting up the Ratio
((vT)₁)/((vT)₂) = ((r₁)/(r₂))²

Substituting the given values: r₁ = 6 mm, (vT)₁ = 20 cm/s r₂ = 3 mm

Step 2: Final Conclusion
(20)/((vT)₂) = ((6)/(3))² (20)/((vT)₂) = 2² = 4 (vT)₂ = (20)/(4) = 5 cm/s
Pattern Recognition

Terminal velocity is directly proportional to the square of the radius. Halving the radius (6 → 3) will drop the terminal velocity by a factor of 1/4.

Chapter Mix

Class 11 Physics: Mechanical Properties of Fluids

Q33 jee_main_2026_22_january_morning Pascal's Law and Surface Tension
Given below are two statements: Statement I : Pressure of fluid is exerted only on a solid surface in contact as the fluid-pressure does not exist everywhere in a still fluid. Statement II: Excess potential energy of the molecules on the surface of a liquid, when compared to interior, results in surface tension. In the light of the above statements, choose the correct answer from the options given below:
  • A. Statement I is true but Statement II is false
  • B. Both Statement I and Statement II are false
  • C. Both Statement I and Statement II are true
  • D. Statement I is false but Statement II is true

Solution

Related Formula
P = (F)/(A), Surface Tension ∝ Δ U
Core Logic

According to Pascal's law, pressure exists at every point in a liquid at rest, not just at boundaries. Thus, Statement I is false.

For interior molecules, net cohesive forces are zero, whereas surface molecules possess excess potential energy leading to surface tension. Thus, Statement II is correct.

Pattern Recognition

Sees: Fluid pressure definition + surface tension origin. Shortcut: Recall Pascal's law (pressure everywhere) and surface energy excess. Check: Matches option (4). ✓

Chapter Mix

Class 11 Physics: Mechanical Properties of Fluids

Q34 jee_main_2026_22_january_evening Capillarity and Surface Tension
When a part of a straight capillary tube is placed vertically in a liquid, the liquid raises up to certain height h. If the inner radius of the capillary tube, density of the liquid and surface tension of the liquid decrease by 1 % each, then the height of the liquid in the tube will change by ____%.
  • A. -1
  • B. +3
  • C. -3
  • D. +1

Solution

Related Formula
h = (2T θ)/(ρ g r) (Δ h)/(h)% = (Δ T)/(T)% - (Δ ρ)/(ρ)% - (Δ r)/(r)%
Core Logic

Applying fractional error analysis to the capillary rise formula:

(Δ h)/(h)% = (-1%) - (-1%) - (-1%) (Δ h)/(h)% = -1 + 1 + 1 = +1%

Capillary tube rise calculation diagram for Q34 - JEE Main 2026 Evening
Capillary tube rise calculation diagram for Q34 - JEE Main 2026 Evening

Step 1: Final Conclusion

The height of the liquid in the tube increases by +1%.

Pattern Recognition

Percentage error in capillary rise: h ∝ (T)/(ρ r). Decreasing numerator T by 1% reduces h by 1% (-1%). Decreasing denominators ρ and r by 1% each increases h by 1% twice (+1% + 1%). Net change: -1 + 1 + 1 = +1%.

Chapter Mix

Class 11 Physics: Mechanical Properties of Fluids

More Mechanical Properties of Fluids Questions — jee_main_2025_28_jan_morning

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