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Chemical Bonding and Molecular Structure appeared 42 times across 3 years — 4.9% of Chemistry. This question is from Molecular Orbital Theory.

Year 2026 2025 2024 Total
Questions 12 14 16 42

Which of the following molecules(s) show/s paramagnetic behavior? (A) O₂ (B) N₂ (C) F₂ (D) S₂ (E) Cl₂ Choose the correct answer from the options given below:

Solution & Explanation

Related Formula

Paramagnetism Presence of at least one unpaired electron in the molecular orbitals.

Core Logic

According to Molecular Orbital Theory (MOT):

  • O₂ has 16 electrons. Its outer configuration contains two unpaired electrons in the anti-bonding orbitals: π2pₓ = π2py. Thus, it is paramagnetic.
  • S₂ belongs to the same oxygen family group and shares an analogous valence configuration with two unpaired electrons in its anti-bonding π^* orbitals. Hence, it is also paramagnetic.
  • N₂ (14e-), F₂ (18e-), and Cl₂ (34e-) have completely paired electronic systems and behave diamagnetically.
Pattern Recognition

Both O₂ and S₂ contain 2 unpaired electrons in their highest occupied molecular orbitals, making them classic examples of paramagnetic diatomic species.

Chapter Mix

Class 11 Chemistry: Chemical Bonding and Molecular Structure

Reference Study Guides

More Chemical Bonding and Molecular Structure Previous-Year Questions — Page 9

Q77 jee_main_2024_31_jan_morning Molecular Orbital Theory
The linear combination of atomic orbitals to form molecular orbitals takes place only when the combining atomic orbitals A. have the same energy B. have the minimum overlap C. have same symmetry about the molecular axis D. have different symmetry about the molecular axis Choose the most appropriate from the options given below:
  • A. A, B, C only
  • B. A and C only
  • C. B, C, D only
  • D. B and D only

Solution

Core Logic

Conditions for the linear combination of atomic orbitals (LCAO) to form molecular orbitals:

  • The combining atomic orbitals must have the same or nearly the same energy.
  • The combining atomic orbitals must have the same symmetry about the molecular axis.
  • The combining atomic orbitals must overlap to the maximum extent (not minimum).
Chapter Mix

Class 11 Chemistry: Chemical Bonding and Molecular Structure

Q85 jee_main_2024_31_jan_morning Hybridization
The number of species from the following in which the central atom uses sp³ hybrid orbitals in its bonding is NH₃, SO₂, SiO₂, BeCl₂, CO₂, H₂O, CH₄, BF₃
Numerical Answer. Answer: 4 to 4

Solution

Core Logic

Analyzing the hybridization of the central atom in each species:

  • NH₃: 3 bp + 1 lp = 4 electron domains arrow sp³
  • SO₂: 2 bp + 1 lp = 3 electron domains arrow sp²
  • SiO₂: A giant covalent network where each Si is bonded to 4 oxygens tetrahedrally arrow sp³
  • BeCl₂: 2 bp + 0 lp = 2 electron domains arrow sp
  • CO₂: 2 bp + 0 lp = 2 electron domains arrow sp
  • H₂O: 2 bp + 2 lp = 4 electron domains arrow sp³
  • CH₄: 4 bp + 0 lp = 4 electron domains arrow sp³
  • BF₃: 3 bp + 0 lp = 3 electron domains arrow sp²
  • Total species with sp³ hybridization: NH₃, SiO₂, H₂O, CH₄. Total count = 4.

Chapter Mix

Class 11 Chemistry: Chemical Bonding and Molecular Structure

More Chemical Bonding and Molecular Structure Questions — jee_main_2025_04_april_morning

Practice all Chemical Bonding and Molecular Structure previous-year questions →

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JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%) | JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%)