Displacement of a wave is expressed as x(t)=5cosleft(628t+fracpi2right)text m. The wavelength of the wave when its velocity is 300 m/s is:

Solution & Explanation

### Related Formula x(t) = Acos(omega t + phi) v = fracomegaK K = frac2pilambda ### Core Logic From the given wave equation, angular frequency omega = 628text rad/s. Given wave velocity v = 300text m/s. Using the relation v = fracomegaK: 300 = frac628K implies K = frac628300 ### Step 1: Compute Wavelength Substitute K = frac2pilambda: frac2pilambda = frac628300 Since 2pi approx 2 times 3.14 = 6.28, the expression simplifies neatly: frac6.28lambda = frac628300 implies lambda = 3text m ### Pattern Recognition Notice standard values like omega = 628 = 200pi, which means the frequency is exactly 100text Hz. Using v = flambda implies 300 = 100lambda implies lambda = 3text m avoids setting up fractions. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 11 Physics: Waves

Reference Study Guides

More Waves Previous-Year Questions — Page 4

Q45 jee_main_2024_31_jan_morning Organ Pipes
The fundamental frequency of a closed organ pipe is equal to the first overtone frequency of an open organ pipe. If length of the open pipe is 60mathrm~cm, the length of the closed pipe will be:
  • A. 60mathrm~cm
  • B. 45mathrm~cm
  • C. 30mathrm~cm
  • D. 15mathrm~cm

Solution

### Related Formula f_textclosed, fundamental = fracv4L_c f_textopen, 1st overtone = frac2v2L_o ### Core Logic
Organ Pipes diagram for Q45 - JEE Main 2024 Morning
Organ Pipes diagram for Q45 - JEE Main 2024 Morning
Organ Pipes diagram for Q45 - JEE Main 2024 Morning
Organ Pipes diagram for Q45 - JEE Main 2024 Morning
For a closed organ pipe, the fundamental frequency (1st harmonic) is: f_1 = fracvlambda = fracv4L_1 where L_1 is the length of the closed pipe. For an open organ pipe, the first overtone (2nd harmonic) is: f_2 = frac2v2L_2 = fracvL_2 where L_2 is the length of the open pipe (L_2 = 60mathrm\,cm). ### Step 2: Equating Frequencies Given f_1 = f_2: fracv4L_1 = fracvL_2 L_2 = 4L_1 60 = 4 times L_1 L_1 = 15mathrm\,cm ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 11 Physics: Waves

More Waves Questions — jee_main_2025_04_april_evening

Practice all Waves previous-year questions →

Rankbit System
JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%) | JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%)