Two strings (A, B) having linear densities mu_A = 2 times 10^-4text kg/m and mu_B = 4 times 10^-4text kg/m and lengths L_A = 2.5text m and L_B = 1.5text m respectively are joined. Free ends of A and B are tied to two rigid supports C and D, respectively creating a tension of 500 N in the wire. Two identical pulses, sent from C and D ends, take time t_1 and t_2 , respectively, to reach the joint. The ratio t_1/t_2 is :

Solution & Explanation

### Related Formula v = sqrtfracTmu t = fracLv ### Core Logic Given L_A = 2.5text m, L_B = 1.5text m, T = 500text N. Velocity in string A: v_A = sqrtfracTmu_A = sqrtfrac5002 times 10^-4 = sqrt2500000 = 5 sqrt10 times 10^2text m/s Velocity in string B: v_B = sqrtfracTmu_B = sqrtfrac5004 times 10^-4 = sqrt1250000 = 5 sqrt5 times 10^2text m/s ### Step 1: Calculate Ratio of Times Time taken to reach joint: t_1 = fracL_Av_A = frac2.55 sqrt10 times 10^2 t_2 = fracL_Bv_B = frac1.55 sqrt5 times 10^2 Ratio: fract_1t_2 = frac2.55sqrt10 times frac5sqrt51.5 = frac2.51.5 times fracsqrt5sqrt10 = frac53 times frac1sqrt2 fract_1t_2 = frac1.6661.414 approx 1.18 ### Pattern Recognition Time ratio is proportional to fracLsqrtT/mu = L sqrtmu/T. Thus t_1/t_2 = (L_1/L_2) sqrtmu_1/mu_2 directly. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 11 Physics: Waves

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