A diatomic molecule has a dipole moment of 1.2 D$1.2\text{ D}$. If the bond distance is 1AA$1\mathrm{\AA}$, then fractional charge on each atom is _________ × 10⁻¹⁰ esu$\times 10^{-10}\text{ esu}$. (Given: 1 D = 10⁻¹⁸ esu cm$1\text{ D} = 10^{-18}\text{ esu cm}$)

Related Formula

Core Logic

Given dipole moment, μ = 1.2 D = 1.2 × 10⁻¹⁸ esu cm$\mu = 1.2\text{ D} = 1.2 \times 10^{-18}\text{ esu cm}$. Bond distance, d = 1AA = 10⁻⁸ cm$d = 1\mathrm{\AA} = 10^{-8}\text{ cm}$.

We need to find the fractional charge q$q$.

Step 1: Calculation

Step 2: Final Formatting

The question asks for the fractional charge in the form x × 10⁻¹⁰ esu$x \times 10^{-10}\text{ esu}$. Therefore, the value is 1.2$1.2$.

Note: Based on NTA officially accepting 12$12$ (if asked for x × 10⁻¹¹$x \times 10^{-11}$) or 1.2$1.2$. We will format it exactly as calculated.

Chapter Mix

Class 11 Chemistry: Chemical Bonding and Molecular Structure