In an experiment to measure the focal length (f) of a convex lens, the magnitude of object distance (x) and the image distance (y) are measured with reference to the focal point of the lens. The y-x plot is shown in figure. The focal length of the lens is ________ mathrmcm.
Lens Formula and Displacement diagram for Q54 - JEE Main 2024 Evening
A graph showing y versus x with a curve passing through the point (20, 20).

Numerical Answer Type:
Enter a numerical value Answer: 20 to 20

Solution & Explanation

### Related Formula textNewton's Lens Formula: x_1 x_2 = f^2 where x_1 and x_2 are object and image distances from the focal points. ### Core Logic Since distances x and y are measured from the focal point (not the optical center), we use Newton's formula: x y = f^2. From the graph, a prominent point on the curve is (20, 20). ### Step 1: Calculate Focal Length 20 times 20 = f^2 f^2 = 400 implies f = 20 mathrm~cm Alternatively using standard lens formula: Object distance from optical center u = -(f + x) Image distance v = +(f + y) frac1v - frac1u = frac1f frac1f+y - frac1-(f+x) = frac1f If x = y = 20 mathrm~cm: frac1f+20 + frac1f+20 = frac1f frac2f+20 = frac1f 2f = f + 20 implies f = 20 mathrm~cm ### Pattern Recognition Whenever distances are specified relative to the focal point, Newton's formula (xy = f^2) instantly solves the problem. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Physics: Ray Optics and Optical Instruments

Reference Study Guides

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Q34 jee_main_2024_31_jan_morning Prism Deviation
The refractive index of a prism with apex angle A is cot(A/2). The angle of minimum deviation is :
  • A. delta_mathrmm = 180^circ - A
  • B. delta_mathrmm = 180^circ - 3A
  • C. delta_mathrmm = 180^circ - 4A
  • D. delta_mathrmm = 180^circ - 2A

Solution

### Related Formula mu = fracsinleft(fracA + delta_m2right)sinleft(fracA2right) ### Core Logic Given that the refractive index mu = cotleft(fracA2right). Substituting this into the prism formula: cotleft(fracA2right) = fracsinleft(fracA + delta_m2right)sinleft(fracA2right) fraccosleft(fracA2right)sinleft(fracA2right) = fracsinleft(fracA + delta_m2right)sinleft(fracA2right) Equating the numerators: cosleft(fracA2right) = sinleft(fracA + delta_m2right) We can rewrite cosine in terms of sine: sinleft(fracpi2 - fracA2right) = sinleft(fracA + delta_m2right) ### Step 2: Solve for Deviation Comparing the angles inside the sine functions: fracpi2 - fracA2 = fracA2 + fracdelta_m2 Multiply the entire equation by 2: pi - A = A + delta_m delta_m = pi - 2A Converting radians to degrees: delta_m = 180^circ - 2A ### Pattern Recognition Whenever refractive index mu = cot(A/2), the relation sin(90^circ - A/2) strictly matches the prism sine equation, meaning minimum deviation delta_m is always 180^circ - 2A. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Physics: Ray Optics And Optical Instruments

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