NEET · Chemistry —

The p-Block Elements appeared 2 times across 1 year — 4.4% of Chemistry. This question is from Anomalous Properties of Elements.

Year 2026 Total
Questions 2 2

Identify the incorrect statement from the following:

Solution & Explanation

Core Logic

(1) Carbon can form pπ - pπ multiple bonds with itself. It is observed in C=C and C ≡ C. (Statement is correct) (2) ECl₃ (E = B and Al): BCl₃ does not form a dimer due to small size of Boron. AlCl₃ forms a dimer Al₂Cl₆ to complete its octet. (Statement is correct) (3) Oxygen exhibits an oxidation state of 0 in O₂, -1 in peroxides (e.g., H₂O₂), -1/2 in superoxides (e.g., KO₂), and +2 in OF₂. Therefore, stating it exhibits only -2 is incorrect. (4) Catenation property of group 14 is highest for Carbon due to strong C-C bonds: C gg Si > Ge ≈ Sn. (Statement is correct)

Step 1: Final Conclusion

Statement (3) is incorrect because Oxygen exhibits multiple oxidation states depending on the compound.

Pattern Recognition

Absolute words like 'only' in oxidation state statements for p-block elements are often false. Oxygen in peroxides, superoxides, and fluorides deviates from the standard -2.

Chapter Mix

Class 11 Chemistry: The p-Block Elements Class 11 Chemistry: Redox Reactions

Reference Study Guides

More The p-Block Elements Previous-Year Questions

Q67 neet_2026_03_may_morning Bonding and Catenation
Identify the incorrect statement from the following:
  • A. P(C₂H₅)₃ and As(C₆H₅)₃ form dπ-dπ bond with transition metals.
  • B. Nitrogen can form dπ -pπ bond with oxygen.
  • C. Nitrogen can form pπ - pπ multiple bonds with itself.
  • D. Phosphorus, arsenic and antimony show catenation property.

Solution

Core Logic

(1) Phosphorus and Arsenic possess vacant d-orbitals. They can act as π-acceptor ligands, forming dπ-dπ backbonds with transition metals. (Correct) (2) Nitrogen (Period 2) does NOT possess vacant d-orbitals in its valence shell. Oxygen also does not have d-orbitals. Therefore, Nitrogen cannot form a dπ-pπ bond with oxygen. (Incorrect) (3) Nitrogen forms strong pπ-pπ multiple bonds with itself (e.g., in N ≡ N). (Correct) (4) Phosphorus, arsenic, and antimony exhibit catenation (e.g., P₄), although to a lesser extent than carbon. (Correct)

Step 1: Final Conclusion

Statement (2) is incorrect because nitrogen lacks d-orbitals.

Pattern Recognition

Period 2 elements (Li, Be, B, C, N, O, F) NEVER form dπ-pπ bonds using their own d-orbitals because they do not have accessible 2d orbitals.

Chapter Mix

Class 12 Chemistry: The p-Block Elements Class 11 Chemistry: Chemical Bonding and Molecular Structure

More The p-Block Elements Questions — neet_2026_03_may_morning

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JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%) | JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%)