The p-Block Elements Previous Year Questions — NEET Chemistry

2 past-year The p-Block Elements questions from NEET (Chemistry).

Q62 (2024)

Identify the incorrect statement from the following:
  1. Carbon has the ability to form $p\pi - p\pi$ multiple bond with itself.
  2. ECl3 (E = B and Al) is a monomer when E = B and a dimer when E = Al.
  3. Oxygen exhibits only -2 oxidation state.
  4. The order of catenation property of Group 14 elements is C >> Si > Ge \approx Sn.
### Core Logic (1) Carbon can form $p\pi - p\pi$ multiple bonds with itself. It is observed in $C=C$ and $C \equiv C$. (Statement is correct) (2) $ECl_3$ (E = B and Al): $BCl_3$ does not form a dimer due to small size of Boron. $AlCl_3$ forms a dimer $Al_2Cl_6$ to complete its octet. (Statement is correct) (3) Oxygen exhibits an oxidation state of 0 in $O_2$, -1 in peroxides (e.g., $H_2O_2$), -1/2 in superoxides (e.g., $KO_2$), and +2 in $OF_2$. Therefore, stating it exhibits *only* -2 is incorrect. (4) Catenation property of group 14 is highest for Carbon due to strong C-C bonds: $C \gg Si > Ge \approx Sn$. (Statement is correct) ### Step 1: Final Conclusion Statement (3) is incorrect because Oxygen exhibits multiple oxidation states depending on the compound. ### Pattern Recognition Absolute words like 'only' in oxidation state statements for p-block elements are often false. Oxygen in peroxides, superoxides, and fluorides deviates from the standard -2. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 11 Chemistry: The p-Block Elements Class 11 Chemistry: Redox Reactions

Q67 (2024)

Identify the incorrect statement from the following:
  1. $\mathrm{P}(\mathrm{C}_{2}\mathrm{H}_{5})_{3}$ and $\mathrm{As}(\mathrm{C}_{6}\mathrm{H}_{5})_{3}$ form $d\pi-d\pi$ bond with transition metals.
  2. Nitrogen can form $\mathrm{d}\pi -\mathrm{p}\pi$ bond with oxygen.
  3. Nitrogen can form $p\pi - p\pi$ multiple bonds with itself.
  4. Phosphorus, arsenic and antimony show catenation property.
### Core Logic (1) Phosphorus and Arsenic possess vacant d-orbitals. They can act as $\pi$-acceptor ligands, forming $d\pi-d\pi$ backbonds with transition metals. (Correct) (2) Nitrogen (Period 2) does NOT possess vacant d-orbitals in its valence shell. Oxygen also does not have d-orbitals. Therefore, Nitrogen cannot form a $d\pi-p\pi$ bond with oxygen. (Incorrect) (3) Nitrogen forms strong $p\pi-p\pi$ multiple bonds with itself (e.g., in $N \equiv N$). (Correct) (4) Phosphorus, arsenic, and antimony exhibit catenation (e.g., $P_4$), although to a lesser extent than carbon. (Correct) ### Step 1: Final Conclusion Statement (2) is incorrect because nitrogen lacks d-orbitals. ### Pattern Recognition Period 2 elements (Li, Be, B, C, N, O, F) NEVER form $d\pi-p\pi$ bonds using their own d-orbitals because they do not have accessible 2d orbitals. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Chemistry: The p-Block Elements Class 11 Chemistry: Chemical Bonding and Molecular Structure
Rankbit System
JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%) | JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%)

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