Solution
Related Formula
Δ H° = Δ U° + Δ ng RT Δ G° = Δ H° - TΔ S°Core Logic
Δ ng = 2 - (2 + 1) = -1 Δ H° = -10 - (1 × 298 × 8.31)/(1000) = -10 - 2.47638 = -12.47638 kJ/mol Δ G° = -12.47638 - (298 × (-44))/(1000) = -12.47638 + 13.112 = +0.63562 kJ/molSince Δ G° > 0, process is non-spontaneous.
Step 1: Conclusion
Δ G° = +0.63568 kJ mol⁻¹ and non-spontaneous.
Pattern Recognition
Positive Δ G° Non-spontaneous reaction under standard conditions.
Chapter Mix
Class 11 Chemistry: Thermodynamics