NEET · Chemistry —

Solutions appeared 2 times across 1 year — 4.4% of Chemistry. This question is from Concentration Terms and Henry's Law.

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Questions 2 2
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Identify the correct statements: (A) The molality of 2.5 g of ethanoic acid (Molar mass: 60 g mol⁻¹) in 75 g of benzene solution is 0.556 m. (B) The molarity of a solution containing 5 g of NaOH (molar mass: 40 g mol⁻¹) in 450 mL of solution is 0.278 M at 298 K. (C) Aquatic species are more comfortable in cold water. (D) The solubility of gas increases with decrease in pressure. (E) For a binary mixture of A and B, the number of moles of A and B are nA and nB respectively. The mole fraction of B will be xB = (nA)/(nA × nB). Choose the correct answer from the options given below:

Solution & Explanation

Related Formula
m = (wB)/(MB) × (1000)/(wA(g)), M = (wB)/(MB) × (1000)/(V(mL))
Core Logic

(A) m = (2.5)/(60) × (1000)/(75) = 0.556 m (Correct). (B) M = (5)/(40) × (1000)/(450) = 0.278 M (Correct). (C) Lower temp higher gas solubility more O₂ in cold water (Correct). (D) Gas solubility increases with increase in pressure (Incorrect). (E) xB = (nB)/(nA + nB) (Incorrect).

Step 1: Conclusion

Statements A, B and C are correct (Option 2).

Pattern Recognition

Verify numerical formulas for molality, molarity, and Henry's law temperature dependence.

Chapter Mix

Class 12 Chemistry: Solutions

Reference Study Guides

Solutions

More Solutions Previous-Year Questions

Q77 neet_2024_05_may_morning Deviations from Raoult's Law
Mixture of chloroform and acetone forms a solution with negative deviation from Raoult's law due to:
  • A. (1) Formation of hydrogen bonding between acetone and chloroform
  • B. (2) Increase in escaping tendency of molecules of each component
  • C. (3) Stronger intermolecular forces between chloroform molecules than those between chloroform and acetone molecules
  • D. (4) Repulsive forces

Solution

Related Formula
CH₃-C(=O)-CH₃ ⋯ H-CCl₃ (Intermolecular Hydrogen Bonding)
Core Logic

Acetone and chloroform form intermolecular hydrogen bonding between oxygen of acetone and acidic hydrogen of chloroform. This increases A-B interactions, causing negative deviation from Raoult's law.

Step 1: Conclusion

Reason is formation of hydrogen bonding (Option 1).

Pattern Recognition

Chloroform + Acetone arrow Hydrogen bonding arrow Stronger solute-solvent attractive forces arrow Negative deviation.

Chapter Mix

Class 12 Chemistry: Solutions

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JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%) | JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%)