NEET · Chemistry —

Hydrocarbons appeared 1 time across 1 year — 2.2% of Chemistry. This question is from Industrial Preparation of Dihydrogen.

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Questions 1 1
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Methane reacts with steam at 1273 K in the presence of nickel catalyst to form:

Solution & Explanation

Related Formula
CH₄(g) + H₂O(g) [1273 K]Ni CO(g) + 3H₂(g)
Core Logic

Steam reforming of methane over nickel catalyst at 1273 K produces carbon monoxide and dihydrogen (water gas synthesis).

Step 1: Conclusion

Products formed are CO and H₂.

Pattern Recognition

Steam reforming of hydrocarbons always produces CO + H₂ mixture (syngas).

Chapter Mix

Class 11 Chemistry: Hydrocarbons

Reference Study Guides

Hydrocarbons

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JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%) | JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%)