NEET · Chemistry —

Coordination Compounds appeared 3 times across 1 year — 6.7% of Chemistry. This question is from Isomerism in Coordination Complexes.

Year 2024 Total
Questions 3 3
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Match List I with List II:
List-I (Complex)List-II (Type of isomerism)
A. [Pt(NH₃)₂Cl₂]I. Optical
B. [Co(en)₃]³⁺(II) Solvate
C. [Co(NH₃)₅NO₂]Cl₂(III) Geometrical
D. [Cr(H₂O)₆]Cl₃(IV) Linkage
Choose the correct answer from the options given below:

Solution & Explanation

Related Formula
Square Planar MA₂B₂ arrow Geometrical, [M(en)₃] arrow Optical
Core Logic

A. [Pt(NH₃)₂Cl₂] shows cis-trans geometrical isomerism (III). B. [Co(en)₃]³⁺ chiral tris-bidentate complex exhibits optical isomerism (I). C. [Co(NH₃)₅NO₂]Cl₂ contains ambidentate NO₂^- ligand showing linkage isomerism (IV). D. [Cr(H₂O)₆]Cl₃ exhibits hydrate/solvate isomerism (II).

Step 1: Conclusion

Matches: A-III, B-I, C-IV, D-II.

Pattern Recognition

Cisplatin arrow Geometrical; [M(en)₃] arrow Optical; NO₂^- arrow Linkage; H₂O arrow Solvate.

Chapter Mix

Class 12 Chemistry: Coordination Compounds

Isomerism structures in coordination complexes
Isomerism structures in coordination complexes
Isomerism structures in coordination complexes
Isomerism structures in coordination complexes

Reference Study Guides

Coordination Compounds

More Coordination Compounds Previous-Year Questions

Q82 neet_2024_05_may_morning Hybridization and Complex Geometry
Match List I with List II:
List I (Complex/ion)List II (Shape/geometry)
A. [Pt(Cl₂)(NH₃)₂](I) Octahedral
B. [Co(NH₃)₆]Cl₃(II) Trigonal bipyramidal
C. [NiCl₄]²⁻(III) Square planar
D. [Fe(CO)₅](IV) Tetrahedral
Choose the correct answer from the options given below:
  • A. (1) A-I, B-III, C-IV, D-II
  • B. (2) A-III, B-IV, C-I, D-II
  • C. (3) A-IV, B-I, C-III, D-II
  • D. (4) A-III, B-I, C-IV, D-II

Solution

Related Formula
dsp² arrow Square Planar, d²sp³ arrow Octahedral, sp³ arrow Tetrahedral, dsp³ arrow Trigonal Bipyramidal
Core Logic

A. [Pt(Cl₂)(NH₃)₂] dsp² Square planar (III). B. [Co(NH₃)₆]Cl₃ d²sp³ Octahedral (I). C. [NiCl₄]²⁻ sp³ Tetrahedral (IV). D. [Fe(CO)₅] dsp³ Trigonal bipyramidal (II).

Step 1: Conclusion

Matches: A-III, B-I, C-IV, D-II.

Pattern Recognition

Platinum(II) complexes are square planar; Cobalt(III) hexammine is octahedral.

Chapter Mix

Class 12 Chemistry: Coordination Compounds

Q84 neet_2024_05_may_morning Types of Ligands - Ambidentate Ligands
Which one of the following is an ambidentate ligand?
  • A. (1) Ethylenediaminetetraacetate ion
  • B. (2) Oxalate
  • C. (3) Ethane-1,2-diamine
  • D. (4) Thiocyanate

Solution

Related Formula
Ambidentate ligand: Contains 2 different donor atoms, but coordinates via only one at a time.
Core Logic

Thiocyanate ion (SCN^-) can bind through either nitrogen (NCS^-) or sulfur (SCN^-). Hence, it is an ambidentate ligand.

Step 1: Conclusion

Ambidentate ligand is Thiocyanate.

Pattern Recognition

Classic ambidentate ligands: NO₂^-, SCN^-, CN^-.

Chapter Mix

Class 12 Chemistry: Coordination Compounds

More Coordination Compounds Questions — neet_2024_05_may_morning

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Rankbit System
JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%) | JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%)