Q82 (2024)
Match List I with List II:
<div style="overflow-x: auto; margin: 1rem 0;"><table style="width: 100%; border-collapse: collapse; text-align: left; font-size: 14px;"><thead><tr><th style="border: 1px solid #888; padding: 8px;">List I (Complex/ion)</th><th style="border: 1px solid #888; padding: 8px;">List II (Shape/geometry)</th></tr></thead><tbody><tr><td style="border: 1px solid #888; padding: 8px;">A. $[Pt(Cl_2)(NH_3)_2]$</td><td style="border: 1px solid #888; padding: 8px;">(I) Octahedral</td></tr><tr><td style="border: 1px solid #888; padding: 8px;">B. $[Co(NH_3)_6]Cl_3$</td><td style="border: 1px solid #888; padding: 8px;">(II) Trigonal bipyramidal</td></tr><tr><td style="border: 1px solid #888; padding: 8px;">C. $[NiCl_4]^{2-}$</td><td style="border: 1px solid #888; padding: 8px;">(III) Square planar</td></tr><tr><td style="border: 1px solid #888; padding: 8px;">D. $[Fe(CO)_5]$</td><td style="border: 1px solid #888; padding: 8px;">(IV) Tetrahedral</td></tr></tbody></table></div>
Choose the correct answer from the options given below:
- (1) A-I, B-III, C-IV, D-II
- (2) A-III, B-IV, C-I, D-II
- (3) A-IV, B-I, C-III, D-II
- (4) A-III, B-I, C-IV, D-II
### Related Formula
$$dsp^2 \rightarrow \text{Square Planar}, \quad d^2sp^3 \rightarrow \text{Octahedral}, \quad sp^3 \rightarrow \text{Tetrahedral}, \quad dsp^3 \rightarrow \text{Trigonal Bipyramidal}$$
### Core Logic
A. $[Pt(Cl_2)(NH_3)_2] \implies dsp^2 \implies$ Square planar (III).
B. $[Co(NH_3)_6]Cl_3 \implies d^2sp^3 \implies$ Octahedral (I).
C. $[NiCl_4]^{2-} \implies sp^3 \implies$ Tetrahedral (IV).
D. $[Fe(CO)_5] \implies dsp^3 \implies$ Trigonal bipyramidal (II).
### Step 1: Conclusion
Matches: A-III, B-I, C-IV, D-II.
### Pattern Recognition
Platinum(II) complexes are square planar; Cobalt(III) hexammine is octahedral.
### Evaluation Rubric / Model Answer
null
### Chapter Mix
Class 12 Chemistry: Coordination Compounds
