For a closed circuit Daniell cell, which of the following plots is the accurate one at a given temperature?

Solution & Explanation

### Core Logic For a closed circuit Daniell cell operating under given conditions, standard cell potential E_textcell^circ remains constant with time during discharge until equilibrium or noticeable concentration shifts occur in a specific manner, or cell potential versus time plots reflect constancy of standard electromotive force terms before polarization effects take over. ### Step 1: Final Conclusion Plot 2 accurately depicts the expected trend where E_textcell^circ remains constant with time. ### Pattern Recognition Sees: graphical representation of electrochemical cell potentials over time. Trap: Confusing standard cell potential E^circ with operating cell potential E_textcell. ### Chapter Mix Class 12 Chemistry: Electrochemistry
Daniell cell plot explanation for Q67 - JEE Main 2026 Evening
Daniell cell plot explanation for Q67 - JEE Main 2026 Evening

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Electrochemistry

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Q72 jee_main_2026_21_jan_morning Conductance of Electrolytic Solutions
The pH and conductance of a weak acid (HX) was found to be 5 and 4 times 10^-5 S, respectively. The conductance was measured under standard condition using a cell where the electrode plates having a surface area of 1text cm^2 were at a distance of 15text cm apart. The value of the limiting molar conductivity is ..... textS m^2text mol^-1. (nearest integer) (Given: degree of dissociation of the weak acid (alpha) ll 1)
Numerical Answer. Answer: 6 to 6

Solution

### Related Formula kappa = G times fraclA Lambda_m = frackappa times 1000C alpha = fracLambda_mLambda_m^infty [H^+] = Calpha ### Core Logic Given: pH = 5, so [H^+] = 10^-5text M. Since [H^+] = C cdot alpha = C cdot fracLambda_mLambda_m^infty, we have 10^-5 = C cdot fracLambda_mLambda_m^infty. First, calculate conductivity (kappa): Conductance G = 4 times 10^-5text S. Cell constant G^* = fraclA = frac15text cm1text cm^2 = 15text cm^-1. kappa = G cdot G^* = (4 times 10^-5) times 15 = 6 times 10^-4text S cm^-1 Molar conductivity (Lambda_m): Lambda_m = frackappa times 1000C = frac6 times 10^-4 times 1000C = frac0.6C Substitute Lambda_m into the proton concentration formula: [H^+] = 10^-5 = C cdot frac0.6 / CLambda_m^infty 10^-5 = frac0.6Lambda_m^infty Lambda_m^infty = frac0.610^-5 = 60000text S cm^2text mol^-1 Convert units to textS m^2text mol^-1: Since 1text m^2 = 10^4text cm^2, Lambda_m^infty = 60000 times 10^-4text S m^2text mol^-1 = 6text S m^2text mol^-1 ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Chemistry: Electrochemistry Class 11 Chemistry: Equilibrium
Q67 jee_main_2026_21_jan_evening Daniell Cell and Cell Potential Variation
For a closed circuit Daniell cell, which of the following plots is the accurate one at a given temperature?
  • A. (1) text Plot 1
  • B. (2) text Plot 2
  • C. (3) text Plot 3
  • D. (4) text Plot 4

Solution

### Core Logic For a closed circuit Daniell cell operating under given conditions, standard cell potential E_textcell^circ remains constant with time during discharge until equilibrium or noticeable concentration shifts occur in a specific manner, or cell potential versus time plots reflect constancy of standard electromotive force terms before polarization effects take over. ### Step 1: Final Conclusion Plot 2 accurately depicts the expected trend where E_textcell^circ remains constant with time. ### Pattern Recognition Sees: graphical representation of electrochemical cell potentials over time. Trap: Confusing standard cell potential E^circ with operating cell potential E_textcell. ### Chapter Mix Class 12 Chemistry: Electrochemistry
Q75 jee_main_2026_21_jan_evening Solubility Product and Electrode Potential
textMX is a sparingly soluble salt that follows the given solubility equilibrium at 298 K: textMX(texts) rightleftharpoons textM^+(textaq) + textX^-(textaq); quad K_textsp = 10^-10 If the standard reduction potential for textM^+(textaq) rightarrow textM(texts) is (E_textM^+/textM^ominus) = 0.79 text V, then the value of the standard reduction potential for the metal/metal insoluble salt electrode E_textX^-/textMX(texts)/textM^ominus is \_\_\_\_ text mV. (nearest integer) [Given: frac2.303RTF = 0.059 text V]
Numerical Answer. Answer: 200 to 200

Solution

### Related Formula E_textX^-/textMX/textM^circ = E_textM^+/textM^circ + frac0.059n log K_textspr ### Core Logic Substituting the given values: E_textX^-/textMX/textM^circ = 0.79 + frac0.0591 log(10^-10) E_textX^-/textMX/textM^circ = 0.79 + 0.059(-10) = 0.79 - 0.59 = 0.20 text V ### Step 1: Converting to Millivolts 0.20 text V = 200 text mV ### Pattern Recognition Sees: relationship between standard reduction potential, solubility product, and metal-insoluble salt electrodes. Trap: Sign or logarithmic base calculation errors. ### Chapter Mix Class 12 Chemistry: Electrochemistry
Q75 jee_main_2026_22_january_morning Solubility Product and Electrode Potential
textMX is a sparingly soluble salt that follows the given solubility equilibrium at 298 K: textMX(texts) rightleftharpoons textM^+(textaq) + textX^-(textaq); quad K_textsp = 10^-10 If the standard reduction potential for textM^+(textaq) rightarrow textM(texts) is (E_textM^+/textM^ominus) = 0.79 text V, then the value of the standard reduction potential for the metal/metal insoluble salt electrode E_textX^-/textMX(texts)/textM^ominus is \_\_\_\_ text mV. (nearest integer) [Given: frac2.303RTF = 0.059 text V]
Numerical Answer. Answer: 200 to 200

Solution

### Related Formula E_textX^-/textMX/textM^circ = E_textM^+/textM^circ + frac0.059n log K_textspr ### Core Logic Substituting the given values: E_textX^-/textMX/textM^circ = 0.79 + frac0.0591 log(10^-10) E_textX^-/textMX/textM^circ = 0.79 + 0.059(-10) = 0.79 - 0.59 = 0.20 text V ### Step 1: Converting to Millivolts 0.20 text V = 200 text mV ### Pattern Recognition Sees: relationship between standard reduction potential, solubility product, and metal-insoluble salt electrodes. Trap: Sign or logarithmic base calculation errors. ### Chapter Mix Class 12 Chemistry: Electrochemistry

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