Solution
Related Formula
For a balanced Wheatstone bridge configuration:
(R₁)/(R₂) = (l₁)/(l₂)Core Logic
When the galvanometer shows zero reading, it implies that the bridge is balanced. The resistance of the wire segments is proportional to their lengths.
Let the length of segment AP be lAP and PB be lPB.
6 ΩRAP = 4 ΩRPBSince R ∝ l:
RAPRPB = lAPlPB = (6)/(4) = (3)/(2)Step 1: Applying Total Length Constraint
We are given the total length:
lAP + lPB = 50 cmUsing the ratio lAP = (3)/(2) lPB:
(3)/(2)lPB + lPB = 50 (5)/(2)lPB = 50 lPB = 20 cmStep 2: Final Conclusion
Solving for lAP:
lAP = 50 - 20 = 30 cmAlternatively, lAP = (3)/(3+2) × 50 = (3)/(5) × 50 = 30 cm.
Pattern Recognition
Null deflection over a uniform wire directly translates resistance ratios into length ratios. Standard Wheatstone bridge application wrapped in potentiometer geometry.
Chapter Mix
Class 12 Physics: Current Electricity