The value of csc 10^circ - sqrt3 sec 10^circ is equal to:

Solution & Explanation

### Related Formula sin(A - B) = sin A cos B - cos A sin B sin 2A = 2 sin A cos A ### Core Logic csc 10^circ - sqrt3 sec 10^circ = frac1sin 10^circ - fracsqrt3cos 10^circ = fraccos 10^circ - sqrt3sin 10^circsin 10^circ cos 10^circ ### Step 1: Sine Transformation Multiply and divide the numerator by 2 to inject standard trig values: = frac2 left(frac12cos 10^circ - fracsqrt32sin 10^circright)sin 10^circ cos 10^circ Substitute sin 30^circ = 1/2 and cos 30^circ = sqrt3/2: = frac2 (sin 30^circ cos 10^circ - cos 30^circ sin 10^circ)sin 10^circ cos 10^circ ### Step 2: Apply Multiple Angle identities The numerator becomes 2 sin(30^circ - 10^circ) = 2 sin 20^circ. Multiply and divide the denominator by 2 to construct sin 2theta: = frac4 sin 20^circ2 sin 10^circ cos 10^circ = frac4 sin 20^circsin 20^circ = 4 ### Pattern Recognition Any expression structured as A csc theta - B sec theta instantly signals a fraction collapse to 2 sin(alpha - theta) / sin(2theta) via multiplication by 2. When constants are 1 and sqrt3, the anchor is always 30^circ or 60^circ. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 11 Maths: Trigonometric Functions
Trigonometric ratio conversion for Q18 - JEE Main 2026 Morning
Trigonometric ratio conversion for Q18 - JEE Main 2026 Morning

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