Given below are two statements: Statement I: Compound (X), shown below, dissolves in textNaHCO_3$\text{NaHCO}_3$ solution and has two chiral carbon atoms.

Statement II: Compound (Y), shown below, has two carbons with sp^3$sp^3$ hybridization, one carbon with sp^2$sp^2$ and one carbon with sp$sp$ hybridization.

In the light of the above statements, choose the correct answer from the options given below:

### Core Logic - Statement I: Compound X contains a carboxylic acid group (which dissolves in textNaHCO_3$\text{NaHCO}_3$) and possesses two chiral centers. Thus Statement I is true. - Statement II: Compound Y has specific carbon hybridization states matching sp^3$sp^3$, sp^2$sp^2$, and sp$sp$ carbons. Thus Statement II is true. ### Step 1: Final Conclusion Both Statement I and Statement II are true, matching option (3). ### Pattern Recognition Sees: identification of chiral centers and carbon hybridization in organic molecules. Trap: Overlooking carboxylic acid solubility requirements in textNaHCO_3$\text{NaHCO}_3$. ### Chapter Mix Class 11 Chemistry: Organic Chemistry - Some Basic Principles and Techniques