jee_main_2026_21_jan_morning - Thermodynamics Topics

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Sample Questions in this Chapter

QUESTION #49 Internal Energy
10 mole of oxygen is heated at constant volume from 30°C to 40°C. The change in the internal energy of the gas is ____ cal. (The molecular specific heat of oxygen at constant pressure, Cₚ = 7 cal./mol °C and R = 2 cal./mol °C.)
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QUESTION #68 Work Done in PV Graph
Which of the following graphs between pressure ‘P’ versus volume ‘V’ represent the maximum work done?
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QUESTION #69 Gibbs Free Energy and Equilibrium
For the reaction, N₂O₄ leftharpoons 2NO₂, graph is plotted as shown below. Identify correct statements. A. Standard free energy change for the reaction is -5.40 kJ mol⁻¹. B. As Δ G in graph is positive, N₂O₄ will not dissociate into NO₂ at all. C. Reverse reaction will go to completion. D. When 1 mole of N₂O₄ changes into equilibrium mixture, value of Δ G = -0.84 kJ mol⁻¹. E. When 2 mole of NO₂ changes into equilibrium mixture, Δ G for equilibrium mixture is -6.24 kJ mol⁻¹. {{IMG1}} Choose the correct answer from the options given below :
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QUESTION #73 Gibbs Free Energy and Equilibrium Constant
Use the following data :
SubstanceΔf H(500K)kJ mol⁻¹S(500K)J K⁻¹ mol⁻¹
AB(g)32222
A₂(g)6146
B₂(g)x280
One mole each of A₂(g) and B₂(g) are taken in a 1L closed flask and allowed to establish the equilibrium at 500K. A₂(g) + B₂(g) leftharpoons 2AB(g) The value of x (in kJ mol⁻¹) is .... (Nearest integer) (Given: K=2.2, R=8.314 J K⁻¹ mol⁻¹)
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JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%) | JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%)

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