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The maximum speed of a boat in still water is 27 \, textkm/h . Now this boat is moving downstream in a river flowing at 9 \, textkm/h . A man in the boat throws a ball vertically upwards with speed of 10 \, textm/s . Range of the ball as observed by an observer at rest on the river bank, is ________ cm. (Take g = 10 \, textm/s^2 ) [cite: 1, 2]

Numerical Answer Type:
Enter a numerical value Answer: 2000 to 2000 +4 marks

Solution & Explanation

### Related Formula T = frac2u_yg, quad R = v_x cdot T ### Core Logic
Relative range tracking frame vector
Relative range tracking frame vector
The total horizontal velocity components combine due to downstream motion addition [cite: 2, 730]: v_x = 27 + 9 = 36text km/h = 36 cdot frac518 = 10text m/s [cite: 730, 740] The time of flight for the vertical launch tracking stands at : T = frac2 cdot 1010 = 2text s Horizontal range measured along the river bank frame is : Range = v_x cdot T = 10 cdot 2 = 20text m = 2000text cm ### Chapter Mix Class 11 Physics: Motion in a Straight Line Class 11 Physics: Motion in a Plane

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