Solution
Related Formula
v = √((γ RT)/(M))Core Logic
For Oxygen (O₂) at standard temperature and pressure (S.T.P.): T = 273 K M = 32 g/mol = 32 × 10⁻³ kg/mol γ = 1.4 R = 8.3 J K⁻¹ mol⁻¹
Step 1: Calculate Velocity
v = 1.4 × 8.3 × 27332 × 10⁻³ v = 3172.2632 × 10⁻³ v = √(99.133 × 10³) v = √(99133) ≈ 314.85 m/sApproximating to the closest given option yields 310 m/s.
Pattern Recognition
For diatomic gases around room temp or STP, velocities range roughly from 250 to 350 m/s depending on molar mass (N₂ ≈ 334, O₂ ≈ 315). Recognize 315 is closest to option (1) due to standard approximations taken in exams.
Chapter Mix
Class 11 Physics: Waves Class 11 Physics: Kinetic Theory of Gases