Which of the following circuits has the same output as that of the given circuit?

Q: Which of the following circuits has the same output as that of the given circuit?

### Core Logic Let's perform Boolean analysis on the configuration steps mapped below: Factoring using distributive Boolean rules: ### Step 1: Final Reduction The expression reduces to a simple inverter (NOT gate) processing input A. This aligns with Circuit (1), matching option (1). ### Pattern Recognition Identify standard combinations: (A AND NOT B) OR (A AND B) collapses back into simply input A because operand B covers all possible states. ### Evaluation Rubric / Model Answer null ### Chapt

Q jee_main_2025_29_jan_morning Logic Gates

Logic Gates diagram for Q15 - JEE Main 2025 Morning — The image features a digital circuit blueprint constructed from basic logic gates with inputs A and B mapped to an output Y.

For the circuit shown above, equivalent GATE is :

A. OR gate
B. NOT gate
C. AND gate
D. NAND gate

Solution

Core Logic

Evaluating the given logic gate diagram combination step-by-step for all input permutations yields the following truth table :

Input A	Input B	Output Y
0	0	0
0	1	1
1	0	1
1	1	1

This behavior matches an OR Gate configuration perfectly.

Chapter Mix

Class 12 Physics: Semiconductor Electronics

Q jee_main_2024_01_february_morning Zener Diode

In the given circuit if the power rating of Zener diode is

10~mW

, the value of series resistance

Rₛ

to regulate the input unregulated supply is:

Zener Diode voltage regulation circuit for Q33 - JEE Main 2024 Morning — The diagram illustrates a Zener diode stabilizer network with an unregulated input supply of 8V, a Zener voltage of 5V, a series resistor Rs, and a load resistor RL of 1 kOhm.

A. $5~kΩ$ $5\mathrm{~k}\Omega$
B. $10~Ω$ $10\mathrm{~\Omega}$
C. $1~kΩ$ $1\mathrm{~k}\Omega$
D. $10~kΩ$ $10\mathrm{~k}\Omega$

Solution

Related Formula

Voltage drop across series resistor:

Vₛ = Vᵢₙ - VZ

Load current:

IL = (VZ)/(RL)

Maximum Zener current:

IZmax = (PZ)/(VZ)

Core Logic

Given values: $Vᵢₙ = 8~V$ $V_{\text{in}} = 8\mathrm{~V}$, $VZ = 5~V$ $V_Z = 5\mathrm{~V}$, $RL = 1~kΩ$ $R_L = 1\mathrm{~k}\Omega$, $PZ = 10~mW$ $P_Z = 10\mathrm{~mW}$.

Voltage across $Rₛ$ $R_s$:

VRₛ = 8 - 5 = 3~V

Current through the load resistor:

IL = (5)/(1 \times 10³) = 5~mA

Maximum current allowed through the Zener diode:

IZmax = 10 \times 10⁻³5 = 2~mA

Step 1: Determine the Range of Resistance

Total current through the series loop: $Iₛ = IZ + IL$ $I_s = I_Z + I_L$

For maximum safety configuration (Zener operating at peak current):

Ismax = IZmax + IL = 2~mA + 5~mA = 7~mA

Rsmin = VRₛIsmax = 3~V7~mA = (3)/(7)~kΩ \approx 428.6~Ω

For minimum Zener current requirement ( $IZ \to 0$ $I_Z \to 0$):

Ismin = 0 + 5~mA = 5~mA

Rsmax = VRₛIsmin = 3~V5~mA = (3)/(5)~kΩ = 600~Ω

Therefore, the required window for regulation is:

(3)/(7)~kΩ < Rₛ < (3)/(5)~kΩ

Step 2: Note on Official Key

None of the given multiple-choice options fall strictly within the stable bounds $[428.6~Ω, 600~Ω]$ . Officially, the answer key evaluates option (3) as correct, though the problem functions fundamentally as a bonus candidate under rigorous design tolerances.

Pattern Recognition

Always solve the current constraints at both boundaries ( $IZ = 0$ $I_{Z} = 0$ and $IZ = Imax$ $I_{Z} = I_{\text{max}}$) to bracket the allowable series resistor zone.

Chapter Mix

Class 12 Physics: Semiconductor Electronics

Q jee_main_2024_27_jan_morning Diode Biasing

Which of the following circuits is reverse-biased?

A.
B. Circuit Schematic B
C.
D. Circuit Schematic D

Solution

Core Logic

For a p-n junction diode to be reverse-biased, the p-side must be connected to a lower electrical potential relative to the n-side.

Evaluating option (4): The p-side is at $-10 V$ $-10\text{ V}$ and the n-side is at $+2 V$ $+2\text{ V}$. Since $Vₚ < Vₙ$ $V_p < V_n$, this circuit is explicitly reverse-biased.

Pattern Recognition

Always calculate $Vₚ - Vₙ$ $V_p - V_n$. If $Δ V < 0$ $\Delta V < 0$, it is reverse biasing; if $Δ V > 0$ $\Delta V > 0$, it is forward biasing.

Chapter Mix

Class 12 Physics: Semiconductor Electronics

Q jee_main_2024_29_jan_morning Zener Diode as a Voltage Regulator

In the given circuit, the breakdown voltage of the Zener diode is

3.0 ~V

. What is the value of

Iz

?

Zener Diode regulator circuit diagram for Q31 - JEE Main 2024 Morning — The image shows a circuit diagram with a 10V DC source connected in series with a 1kΩ resistor, followed by a parallel combination of a Zener diode (with current Iz) and a 2kΩ load resistor.

A. $3.3 ~mA$ $3.3 \mathrm{~mA}$
B. $5.5 ~mA$ $5.5 \mathrm{~mA}$
C. $10 ~mA$ $10 \mathrm{~mA}$
D. $7 ~mA$ $7 \mathrm{~mA}$

Solution

Related Formula

For a parallel circuit regulator using a Zener diode:

$I = Iz + I₁$ $I = I_z + I_1$

where, $I$ $I$ = total current through the series resistor $Iz$ $I_z$ = current through the Zener diode $I₁$ $I_1$ = current through the load resistor

Core Logic

Given that the breakdown voltage of the Zener diode is:

Vz = 3.0 ~V

Let potential at junction $B$ $B$ and $D$ $D$ be $0 ~V$ $0 \mathrm{~V}$. Then, the potential at the Zener cathode $A$ $A$ and load node $C$ $C$ is stabilized at:

VA = VC = 3.0 ~V

Potential at the source input $E$ $E$ is $10 ~V$ $10 \mathrm{~V}$.

Step 1: Calculate Total Current

The potential drop across the series resistor ( $1 ~kΩ$ $1 \mathrm{~k}\Omega$) is:

Δ V = 10 ~V - 3 ~V = 7 ~V

Hence, the total line current $I$ $I$ is:

I = 7 ~V1000 Ω = 7 \times 10⁻³ ~A = 7 ~mA

Zener Diode resolved current distributions for Q31 - JEE Main 2024 Morning — The image shows a circuit diagram with a 10V DC source connected in series with a 1kΩ resistor, followed by a parallel combination of a Zener diode (with current Iz) and a 2kΩ load resistor.

Step 2: Calculate Load Current

The voltage across the load resistor ( $2 ~kΩ$ $2 \mathrm{~k}\Omega$) is equal to $Vz = 3 ~V$ $V_z = 3 \mathrm{~V}$. Thus, the load current $I₁$ $I_1$ is:

I₁ = 3 ~V2000 Ω = 1.5 \times 10⁻³ ~A = 1.5 ~mA

Step 3: Calculate Zener Current

By applying Kirchhoff's Current Law at node $A$ $A$:

Iz = I - I₁ = 7 ~mA - 1.5 ~mA = 5.5 ~mA

Therefore, the current through the Zener diode is $5.5 ~mA$ $5.5 \mathrm{~mA}$.

Pattern Recognition

Whenever you see a Zener diode in breakdown connected parallel to a load, always fix the node potential at the breakdown voltage. Work backwards from the supply potential to find the total current, calculate the load current using Ohm's law, and subtract to find the Zener current.

Chapter Mix

Class 12 Physics: Semiconductor Electronics: Materials, Devices and Simple Circuits

Q jee_main_2024_30_january_evening Diode Circuits

In the given circuit, the voltage across load resistance

(RL)

is:

Diode Circuits diagram for Q45 - JEE Main 2024 Evening — A parallel combination of a Germanium diode (D1) and a Silicon diode (D2) connected in series with a 1.5 k ohm resistor and a 15V battery. A load resistor RL (2.5 k ohm) is in series.

A. $8.75 ~V$ $8.75 \mathrm{~V}$
B. $9.00 ~V$ $9.00 \mathrm{~V}$
C. $8.50 ~V$ $8.50 \mathrm{~V}$
D. $14.00 ~V$ $14.00 \mathrm{~V}$

Solution

Core Logic

The circuit contains a Germanium diode ( $D₁$ $D_1$) and a Silicon diode ( $D₂$ $D_2$) in parallel. The barrier potential for Germanium is $0.3 ~V$ $0.3 \mathrm{~V}$ and for Silicon is $0.7 ~V$ $0.7 \mathrm{~V}$. Since they are in parallel, the diode with the lower barrier potential (Ge) will turn on first. Once the Germanium diode starts conducting, it clamps the voltage across the parallel combination to $0.3 ~V$ $0.3 \mathrm{~V}$, preventing the Silicon diode from ever turning on. Thus, only $D₁$ $D_1$ conducts.

Step 1: Calculate Total Current

The total voltage in the loop after considering the Ge diode's drop is:

Vₙₑₜ = 15 ~V - 0.3 ~V = 14.7 ~V

Total resistance in the circuit:

Rtotal = 1.5 ~kΩ + 2.5 ~kΩ = 4.0 ~kΩ

Current $i$ $i$:

i = (14.7)/(4) ~mA

(Note: Some sources approximate $15 - 1 = 14$ $15 - 1 = 14$ if considering ideal diode drops or a misprint in standard problem sets where $Vdrop = 1V$ $V_{\text{drop}} = 1\mathrm{V}$ total across the network, but strictly for Ge $Vb = 0.3V$ $V_b = 0.3\mathrm{V}$, let's check standard solution behavior... Wait, the standard PDF solution explicitly uses $15 ~V - 1 ~V = 14 ~V$ ? No, wait. Let's look at the source PDF: $i = 14 / 4 = 3.5 ~mA$ $i = 14 / 4 = 3.5 \mathrm{~mA}$. This implies a total diode drop of $1 ~V$ $1 \mathrm{~V}$ was assumed in the PDF's logic, which might be an error in the source, but we follow it strictly.) Wait, if the source states $i = 14/4 = 3.5mA$ $i = 14/4 = 3.5\mathrm{mA}$, it means the voltage drop across the diode was taken as $1V$ $1\mathrm{V}$ (which is unusual, maybe $15V$ $15V$ battery has internal resistance or it's a zener?). Looking at the PDF: `i = 14 / 4 = 3.5 mA`. I will transcribe the PDF exactly.

Step 2: Voltage Across Load

VL = i \times RL = 3.5 ~mA \times 2.5 ~kΩ

VL = 8.75 ~V

Pattern Recognition

When Si and Ge diodes are in parallel, the Ge diode (0.3V) dominates and turns on, shutting off the Si diode (0.7V). Although physically $15 - 0.3 = 14.7V$ $15 - 0.3 = 14.7\mathrm{V}$, the provided solution implies an effective $1V$ $1\mathrm{V}$ drop is used to reach the $14V$ $14\mathrm{V}$ net. Follow the specific provided calculation.

Chapter Mix

Class 12 Physics: Semiconductor Electronics: Materials, Devices and Simple Circuits

Which of the following circuits has the same output as that of the given circuit? A combination gate circuit configuration evaluated for total Boolean output expressions.

Solution & Explanation

Core Logic

Step 1: Final Reduction

Pattern Recognition

Chapter Mix

More Semiconductor Electronics: Materials, Devices and Simple Circuits Previous-Year Questions — Page 5

Solution

Core Logic

Chapter Mix

Solution

Related Formula

Core Logic

Step 1: Determine the Range of Resistance

Step 2: Note on Official Key

Pattern Recognition

Chapter Mix

Solution

Core Logic

Pattern Recognition

Chapter Mix

Solution

Related Formula

Core Logic

Step 1: Calculate Total Current

Step 2: Calculate Load Current

Step 3: Calculate Zener Current

Pattern Recognition

Chapter Mix

Solution

Core Logic

Step 1: Calculate Total Current

Step 2: Voltage Across Load

Pattern Recognition

Chapter Mix

More Semiconductor Electronics: Materials, Devices and Simple Circuits Questions — jee_main_2025_28_jan_morning

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Which of the following circuits has the same output as that of the given circuit?
A combination gate circuit configuration evaluated for total Boolean output expressions.