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Which of the following figure represents the relation between Celsius and Fahrenheit temperatures?

Solution & Explanation

### Related Formula fracC5 = fracF - 329 ### Core Logic Rearranging the conversion identity to express C as a function of F: C = frac59F - frac1609 This is a straight line equation y = mx + c with: - Positive slope m = frac59 - Negative y-intercept c = -frac1609 (at F=0, C approx -17.8^circmathrmC) - Positive x-intercept at C=0, F=32 This completely matches the layout shown in Graph (2).
Correct linear plot for Celsius vs Fahrenheit conversion Q10
celsius fahrenheit graph, temperature conversion line, linear scaling
### Pattern Recognition 0^circmathrmC = 32^circmathrmF. Therefore, the line must cross the positive side of the horizontal F axis when C=0. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 11 Physics: Thermal Properties of Matter

Reference Study Guides

Thermal Properties Of Matter

More Thermal Properties of Matter Previous-Year Questions — Page 2

Q16 2025 Newton's Law of Cooling
The temperature of a body in air falls from 40^circC to 24^circC in 4 minutes. The temperature of the air is 16^circC. The temperature of the body in the next 4 minutes will be:
  • A. frac143^circmathrmC
  • B. frac283^circmathrmC
  • C. frac563^circmathrmC
  • D. frac423^circmathrmC

Solution

### Related Formula fracT_1 - T_2t = Kleft[fracT_1 + T_22 - T_s ight] ### Core Logic For the first interval (40^circmathrmC to 24^circmathrmC in 4\ mathrmmin with T_s = 16^circmathrmC): frac40 - 244 = Kleft[frac40 + 242 - 16 ight] frac164 = K[32 - 16] implies 4 = 16K implies K = frac14 For the next 4 minutes, let the final temperature be T: frac24 - T4 = frac14left[frac24 + T2 - 16 ight] 24 - T = frac24 + T2 - 16 40 - T = frac24 + T2 80 - 2T = 24 + T implies 3T = 56 implies T = frac563^circmathrmC ### Pattern Recognition Newton's law of cooling approximation works beautifully when temperature differences are small. Always compute K from the first step and substitute directly into the second. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 11 Physics: Thermal Properties of Matter

More Thermal Properties of Matter Questions — jee_main_2025_24_jan_evening

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