Identify the correct statement/s from the following options: (A) -mathrmOCH_3 and -mathrmNHCOCH_3 are activating groups (B) -mathrmCN and -mathrmOH are meta directing groups (C) -mathrmCN and -mathrmSO_3mathrmH are meta directing groups (D) Activating groups act as ortho- and para- directing groups (E) Halides are activating groups Choose the correct answer from the options given below :

Solution & Explanation

### Core Logic Let's evaluate each statement based on electrophilic aromatic substitution guidelines: * Statement (A): Both -mathrmOCH_3 and -mathrmNHCOCH_3 have lone pairs on the atom directly attached to the benzene ring. These lone pairs undergo resonance delocalization into the ring, increasing electron density and activating it toward substitution. This statement is true. * Statement (B): While -mathrmCN is a deactivating meta-directing group, -mathrmOH is a strongly activating ortho/para-directing group due to resonance. This statement is false. * Statement (C): Both -mathrmCN and -mathrmSO_3mathrmH withdraw electron density via inductive and resonance effects (-I, -M). This deactivates the ring and directs substitution to the meta position. This statement is true. * Statement (D): Activating groups increase electron density primarily at the ortho and para positions via resonance, directing incoming electrophiles to those sites. This statement is true. * Statement (E): Halogens are an exception: they are deactivating due to their strong inductive effect (-I), but ortho/para-directing due to resonance (+M). This statement is false. Therefore, statements (A), (C), and (D) are correct, which matches Option (1). ### Pattern Recognition Groups that activate the aromatic ring by donating electrons via resonance always direct incoming electrophiles to the ortho and para positions. Halogens are a unique exception: they deactivate the ring but still direct to the ortho and para positions. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 11 Chemistry: Hydrocarbons Class 12 Chemistry: Haloalkanes and Haloarenes

Reference Study Guides

More Organic Chemistry - Some Basic Principles and Techniques Previous-Year Questions — Page 12

Q62 jee_main_2024_27_jan_morning Isomerism
  • A. Structure A
  • B. Structure B
  • C. Structure C
  • D. Structure D

Solution

### Core Logic The enol form of structure (2) produces a fully conjugated, aromatic ring system (phenol derivative) which provides immense resonance stabilization. Therefore, the equilibrium lies heavily toward the enol form.
Enol conversion pathway diagram for Q62 - JEE Main 2024 Morning
Four choices depicting structure inputs for keto compounds tautomerizing to enols.
### Pattern Recognition Look for enol forms that attain aromaticity. Aromatic stabilization overrides typical keto-preference factors. ### Chapter Mix Class 11 Chemistry: Organic Chemistry - Some Basic Principles and Techniques
Q64 jee_main_2024_27_jan_morning Basic Strength
Which of the following is strongest Bronsted base?
  • A. Option 1
  • B. Option 2
  • C. Option 3
  • D. Option 4

Solution

### Core Logic Option (4) is a cyclic secondary aliphatic amine (piperidine derivative) where the nitrogen atom is textsp^3 hybridized and its lone pair is entirely localized, making it highly available to accept a proton. In contrast, options (1), (2), and (3) have lone pairs involved in resonance with aromatic systems or unsaturated structures.
Lone pair localization logic diagram for Q64 - JEE Main 2024 Morning
Four different amine ring structures listed as options.
### Pattern Recognition Localized aliphatic amines are consistently stronger Bronsted bases than aromatic or delocalized analogs. ### Chapter Mix Class 11 Chemistry: Organic Chemistry - Some Basic Principles and Techniques
Q66 jee_main_2024_27_jan_morning Acidic Strength
Which of the following has highly acidic hydrogen?
  • A. Structure 1
  • B. Structure 2
  • C. Structure 3
  • D. Structure 4

Solution

### Core Logic Option (4) features an active methylene group flanked directly between two electron-withdrawing carbonyl groupings. The removal of a proton from this central -textCH_2- carbon produces a conjugate base that is strongly stabilized via extensive delocalization across both oxygen atoms.
Conjugate base stabilization resonance scheme for Q66 - JEE Main 2024 Morning
Four carbonyl organic structures presented as options.
### Pattern Recognition Look for hydrogens between two -M / -I carbonyl complexes rightarrow Active methylene effect. ### Chapter Mix Class 11 Chemistry: Organic Chemistry - Some Basic Principles and Techniques
Q74 jee_main_2024_27_jan_morning Classification of Organic Compounds
Cyclohexene is textquadquad type of an organic compound.
  • A. Benzenoid aromatic
  • B. Benzenoid non-aromatic
  • C. Acyclic
  • D. Alicyclic

Solution

### Core Logic Cyclohexene features an aliphatic carbon ring framework containing an unsaturated double bond but lacks an aromatic sextet ring structure. It belongs to the alicyclic category (aliphatic + cyclic compounds).
Cyclohexene chemical ring diagram for Q74 - JEE Main 2024 Morning
Cyclohexene chemical ring diagram for Q74 - JEE Main 2024 Morning
### Chapter Mix Class 11 Chemistry: Organic Chemistry - Some Basic Principles and Techniques
Q77 jee_main_2024_27_jan_morning IUPAC Nomenclature
IUPAC name of following compound (P) is:
Substituted ring framework structural layout for Q77 - JEE Main 2024 Morning
Substituted cyclohexane molecule labeled as compound P.
Substituted ring framework structural layout for Q77 - JEE Main 2024 Morning
Substituted cyclohexane molecule labeled as compound P.
  • A. 1-Ethyl-5, 5-dimethylcyclohexane
  • B. 3-Ethyl-1,1-dimethylcyclohexane
  • C. 1-Ethyl-3, 3-dimethylcyclohexane
  • D. 1,1-Dimethyl-3-ethylcyclohexane

Solution

### Core Logic Number the ring to give substituents the lowest possible locants. Setting locant 1 at the carbon carrying the two methyl groups provides a locant list of (1,1,3), whereas setting it at the ethyl-bearing carbon gives (1,3,3). The set (1,1,3) wins by the lowest locant rule. Then arrange alphabetically: 3-ethyl precedes 1,1-dimethyl. Hence, the correct systematic tag is 3-Ethyl-1,1-dimethylcyclohexane.
Locant indexing direction chart for Q77 - JEE Main 2024 Morning
Substituted cyclohexane molecule labeled as compound P.
### Pattern Recognition Lowest locant grouping set takes ultimate priority before checking alphabetical organization rules. ### Chapter Mix Class 11 Chemistry: Organic Chemistry - Some Basic Principles and Techniques

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