The correct statements from the following are: (A) Tl³⁺$\text{Tl}^{3+}$ is a powerful oxidising agent (B) Al³⁺$\text{Al}^{3+}$ does not get reduced easily (C) Both Al³⁺$\text{Al}^{3+}$ and Tl³⁺$\text{Tl}^{3+}$ are very stable in solution (D) Tl⁺$\text{Tl}^{+}$ is more stable than Tl³⁺$\text{Tl}^{3+}$ (E) Al³⁺$\text{Al}^{3+}$ and Tl⁺$\text{Tl}^{+}$ are highly stable Choose the correct answer from the options given below:

Core Logic

Oxygen exists naturally as a discrete diatomic element molecule system (O₂$O_2$), displaying an atomicity count equal to 2. In contrast, sulphur forms a puckered multi-atom ring structure configuration (S₈$S_8$), presenting a larger atomicity value equal to 8.

This high structural molecular mass significantly amplifies the surface area available for London dispersion forces. This creates much stronger intermolecular van der Waals attractions within molecular configurations of sulphur, accounting for its significantly elevated thermal properties relative to gaseous oxygen molecules.

Pattern Recognition

O₂$O_2$ molecular setups form simple gaseous configurations, while S₈$S_8$ molecular configurations establish thick, heavy crown-packed chains.

Chapter Mix

Class 11 Chemistry: The p-Block Elements

Related Formula

Specific metal sulfide precipitates exhibit characteristic colors used in qualitative inorganic analysis schemes.

Core Logic

Evaluating the colors of the specified inorganic sulfides:

• (NH₄)₂S$(NH_4)_2S$ (Ammonium sulfide solution / yellow ammonium sulfide compound matrix) arrow$\rightarrow$ Yellow
• PbS$PbS$ (Lead sulfide) arrow$\rightarrow$ Black
• CuS$CuS$ (Copper sulfide) arrow$\rightarrow$ Black
• As₂S₃$As_2S_3$ (Arsenic(III) sulfide) arrow$\rightarrow$ Yellow
• As₂S₅$As_2S_5$ (Arsenic(V) sulfide) arrow$\rightarrow$ Yellow

Step 1: Identifying Valid Items

The sulfides matching the yellow color description are (A), (D), and (E).

Pattern Recognition

In qualitative salt analysis, arsenic belongs to Group IIB and precipitates as a bright yellow sulfide (As₂S₃$As_2S_3$). Transition metal sulfides like PbS$PbS$ and CuS$CuS$ typically form dark black precipitates.

Chapter Mix

Class 12 Chemistry: p-Block Elements

Related Formula

Basic strength order among Group 15 hydrides drops down the group due to an increase in size and a decrease in charge density:

Core Logic

Let's analyze the properties specified:

• The element must be able to form dπ-dπ$d\pi-d\pi$ bonds with transition metals. Nitrogen cannot form these bonds because it lacks vacant d$d$-orbitals in its valence shell. Therefore, nitrogen is excluded.
• Among the remaining elements (Phosphorus, Arsenic, Antimony, Bismuth) that contain available d$d$-orbitals, basic strength decreases down the group. Phosphorus forms phosphine (PH₃$PH_3$), which is the strongest base among the remaining members.

Step 1: Identify the Atomic Number

The identified element is Phosphorus (P$P$).

The atomic number of Phosphorus is 15$15$.

Pattern Recognition

Pay attention to qualifying statements like 'among elements that form dπ-dπ$d\pi-d\pi$ bonds'. This explicitly excludes second-period elements (like Nitrogen), making Phosphorus (Z=15$Z=15$) the top choice for basicity.

Chapter Mix

Class 12 Chemistry: p-Block Elements

Core Logic

NH₃$NH_3$ undergoes extensive intermolecular hydrogen bonding due to the high electronegativity and small size of Nitrogen. PH₃$PH_3$ (Phosphine) molecules are only held together by weak van der Waals (dispersion) forces because Phosphorus is less electronegative and larger, unable to form strong hydrogen bonds.

Step 1: Evaluate Statements

Assertion (A) is correct: PH₃$PH_3$ has a lower boiling point than NH₃$NH_3$ because breaking H-bonds in NH₃$NH_3$ requires more energy. Reason (R) is incorrect: It falsely claims NH₃$NH_3$ has van der Waals association and PH₃$PH_3$ has hydrogen bonding. It is exactly the opposite.

Pattern Recognition

N, O, and F are the only atoms electronegative enough to form stable hydrogen bonds in simple hydrides. Boiling point anomaly: NH₃ > PH₃$NH_3 > PH_3$ purely due to H-bonding in NH₃$NH_3$.

Chapter Mix

Class 12 Chemistry: The p-Block Elements Class 11 Chemistry: Chemical Bonding and Molecular Structure