Match List-I with List-II.

List-I (Conversion)	List-II (Reagents, Conditions used) [cite: 248, 249]
(A) Chlorobenzene ightarrow$ ightarrow$ Phenol	(I) textWarm, textH_2textO$\text{Warm, } \text{H}_2\text{O}$
(B) p-Nitrochlorobenzene ightarrow$ ightarrow$ p-Nitrophenol	(II) (a) textNaOH, 368text K$\text{NaOH, } 368\text{ K}$; (b) textH3textO^+$\text{H}3\text{O}^+$	(C) 2,4-Dinitrochlorobenzene ightarrow$ ightarrow$ 2,4-Dinitrophenol	(III) (a) textNaOH, 443text K$\text{NaOH, } 443\text{ K}$; (b) textH_3textO^+$\text{H}_3\text{O}^+$	(D) 2,4,6-Trinitrochlorobenzene ightarrow$ ightarrow$ 2,4,6-Trinitrophenol	(IV) (a) textNaOH, 623text K, 300text atm$\text{NaOH, } 623\text{ K, } 300\text{ atm}$; (b) textH_3textO^+$\text{H}_3\text{O}^+$ Choose the correct answer from the options given below: A. text(A)-(II), (B)-(III), (C)-(I), (D)-(IV)$\text{(A)-(II), (B)-(III), (C)-(I), (D)-(IV)}$ B. text(A)-(III), (B)-(IV), (C)-(II), (D)-(I)$\text{(A)-(III), (B)-(IV), (C)-(II), (D)-(I)}$ C. text(A)-(IV), (B)-(III), (C)-(II), (D)-(I)$\text{(A)-(IV), (B)-(III), (C)-(II), (D)-(I)}$ D. text(A)-(IV), (B)-(III), (C)-(I), (D)-(II)$\text{(A)-(IV), (B)-(III), (C)-(I), (D)-(II)}$ Solution & Explanation ### Related Formula textRate of S_NtextAr propto textNumber of electron-withdrawing groups (-I, -M) at ortho/para positions $$\text{Rate of } S_N\text{Ar} \propto \text{Number of electron-withdrawing groups (-I, -M) at ortho/para positions} $$ ### Core Logic Aryl halides are generally unreactive towards nucleophilic substitution due to resonance stabilization of the textC-Cl$\text{C-Cl}$ bond. However, the presence of strong electron-withdrawing groups (-textNO_2$-\text{NO}_2$) at ortho and para positions dramatically increases reactivity by stabilizing the intermediate carbanion: - (A) Chlorobenzene: Needs extreme conditions: textNaOH at 623text K, 300text atm$\text{NaOH at } 623\text{ K, } 300\text{ atm}$ (Dow's Process) ightarrow$ ightarrow$ (IV) - (B) p-Nitrochlorobenzene: One para -textNO_2$-\text{NO}_2$ group softens required temperature to 443text K$443\text{ K}$ ightarrow$ ightarrow$ (III) - (C) 2,4-Dinitrochlorobenzene: Two electron-withdrawing groups lower needed temperature further to 368text K$368\text{ K}$ ightarrow$ ightarrow$ (II) - (D) 2,4,6-Trinitrochlorobenzene: Highly activated picryl chloride hydrolyzes smoothly with just warm water ightarrow$ ightarrow$ (I) ### Step 1: Final Match Alignment Matching sequences cleanly yields: (A)-(IV), (B)-(III), (C)-(II), (D)-(I). ### Pattern Recognition The more -textNO_2$-\text{NO}_2$ groups present on the ring, the less aggressive the reagent/temperature setup required. Count -textNO_2$-\text{NO}_2$ groups: 0 ightarrow 623textK$0 ightarrow 623\text{K}$, 1 ightarrow 443textK$1 ightarrow 443\text{K}$, 2 ightarrow 368textK$2 ightarrow 368\text{K}$, 3 ightarrow textwarm water$3 ightarrow \text{warm water}$. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Chemistry: Haloalkanes and Haloarenes Reference Study Guides Haloalkanes And Haloarenes Keywords: #Dows process chlorobenzene #JEE Main 2025 Evening Q32 #nucleophilic aromatic substitution kinetics #picryl chloride hydrolysis More Haloalkanes and Haloarenes Previous-Year Questions — Page 6 Q67 jee_main_2024_31_jan_evening IUPAC Nomenclature of Haloalkanes Identify structure of 2,3-dibromo-1-phenylpentane. A. text(1) Structure A$\text{(1) Structure A}$ B. text(2) Structure B$\text{(2) Structure B}$ C. text(3) Structure C$\text{(3) Structure C}$ D. text(4) Structure D$\text{(4) Structure D}$ Solution ### Core Logic Decode the IUPAC name: 2,3-dibromo-1-phenylpentane. 1) Parent chain is pentane (5 carbon chain: C1-C2-C3-C4-C5). 2) Substituents: - Phenyl group at position 1. - Bromo groups at positions 2 and 3. Option (3) correctly displays a 5-carbon straight chain. The first carbon attaches to the benzene ring (phenyl group), and the second and third carbons each hold a bromine atom. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Chemistry: Haloalkanes and Haloarenes Q68 jee_main_2024_31_jan_morning Elimination and Addition Reactions The product (C) in the below mentioned reaction is: CH_3-CH_2-CH_2-Br xrightarrow[Delta]KOH_(alc) A xrightarrow[Delta]HBr B xrightarrow[Delta]KOH_(aq) C$$CH_3-CH_2-CH_2-Br \xrightarrow[\Delta]{KOH_{(alc)}} A \xrightarrow[\Delta]{HBr} B \xrightarrow[\Delta]{KOH_{(aq)}} C$$ A. textPropan-1-ol$\text{Propan-1-ol}$ B. textPropene$\text{Propene}$ C. textPropyne$\text{Propyne}$ D. textPropan-2-ol$\text{Propan-2-ol}$ Solution ### Step 1: Elimination to form Propene CH_3-CH_2-CH_2-Br xrightarrowtextKOH (alc), Delta CH_3-CH=CH_2 quad text(Compound A: Propene)$$CH_3-CH_2-CH_2-Br \xrightarrow{\text{KOH (alc), } \Delta} CH_3-CH=CH_2 \quad \text{(Compound A: Propene)}$$ ### Step 2: Electrophilic Addition of HBr Addition of HBr$HBr$ follows Markovnikov's rule: CH_3-CH=CH_2 + HBr xrightarrowDelta CH_3-CH(Br)-CH_3 quad text(Compound B: 2-Bromopropane)$$CH_3-CH=CH_2 + HBr \xrightarrow{\Delta} CH_3-CH(Br)-CH_3 \quad \text{(Compound B: 2-Bromopropane)}$$ ### Step 3: Nucleophilic Substitution Reaction with aqueous KOH leads to S_N2/S_N1$S_N2/S_N1$ substitution of Br^-$Br^-$ with OH^-$OH^-$: CH_3-CH(Br)-CH_3 xrightarrowtextKOH (aq), Delta CH_3-CH(OH)-CH_3 quad text(Compound C: Propan-2-ol)$$CH_3-CH(Br)-CH_3 \xrightarrow{\text{KOH (aq), } \Delta} CH_3-CH(OH)-CH_3 \quad \text{(Compound C: Propan-2-ol)}$$ ### Pattern Recognition Alc. KOH gives elimination (alkene). Aq. KOH gives substitution (alcohol). HBr$HBr$ on unsymmetrical alkene gives Markovnikov addition. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Chemistry: Haloalkanes and Haloarenes Q86 jee_main_2024_31_jan_morning Elimination and Substitution CH_3CH_2Br + NaOH rightarrow textProduct A$$CH_3CH_2Br + NaOH \rightarrow \text{Product A}$$ CH_3CH_2Br + NaOH / H_2O rightarrow textProduct B$$CH_3CH_2Br + NaOH / H_2O \rightarrow \text{Product B}$$ The total number of hydrogen atoms in product A and product B is Numerical Answer. Answer: 10 to 10 Solution ### Core Logic Reaction 1: If the reagent is alcoholic NaOH (implied due to formation of a distinct product A to contrast B), elimination occurs: CH_3CH_2Br + NaOH (textalc) rightarrow CH_2=CH_2 text (Ethene)$$CH_3CH_2Br + NaOH (\text{alc}) \rightarrow CH_2=CH_2 \text{ (Ethene)}$$ Hydrogen atoms in ethene (C_2H_4$C_2H_4$) = 4. Reaction 2: If the reagent is aqueous NaOH (NaOH / H_2O$NaOH / H_2O$), nucleophilic substitution (S_N2$S_N2$) occurs: CH_3CH_2Br + NaOH (textaq) rightarrow CH_3CH_2OH text (Ethanol)$$CH_3CH_2Br + NaOH (\text{aq}) \rightarrow CH_3CH_2OH \text{ (Ethanol)}$$ Hydrogen atoms in ethanol (C_2H_6O$C_2H_6O$) = 6. Total hydrogen atoms = 4 + 6 = 10. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Chemistry: Haloalkanes and Haloarenes More Haloalkanes and Haloarenes Questions — jee_main_2025_07_april_evening Practice all Haloalkanes and Haloarenes previous-year questions → The major product of the following reaction is: Given below are two statements : Statement I: will undergo Which among the following halides will generate the most stable The product B formed in the following reaction sequence is The products A and B in the following reactions, respectively Given below are two statements: Statement (I): is more polar The structure of the major product formed in the following Given below are two statements : Statement-I: The conversion proceeds Consider the following sequence of reactions: Consider the above sequence A hydrocarbon ‘P’ ( ) on reaction with HCl gives Given below are two statements : one is labelled as Given below are two statements: Statement I: High concentration of Identify A and B in the following reaction sequence. Identify structure of 2,3-dibromo-1-phenylpentane. The product (C) in the below mentioned reaction is: Example of vinylic halide is Given below are two statements : one is labelled as Given below are two statement one is labeled as Assertion The correct statement regarding nucleophilic substitution reaction in a chiral Number of optical isomers possible for 2-chlorobutane The total number of hydrogen atoms in product A and Total number of optically active isomers shown by , obtained SYSTEM Syllabus Analysis & Trend Mapping Dashboard Chapter Trends Formula Recognition Questions Feed Weightage Login Sign Up Dashboard Rankbit System Revise Mistakes Rankbit JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%) | JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%) Report Issue Question Issue Type Wrong Answer Wrong Solution Formula Error Typo / Language Issue Diagram Issue Option Mismatch Duplicate Question Out of Syllabus Other Optional Notes Cancel Submit Report Quick Review Question Accuracy Feedback Accurate Needs Fix Difficulty Feedback Easy Medium Hard Confusion Score Low High Optional Notes Cancel Submit Review Welcome back Continue with Google or Sign In Don't have an account? 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