JEE Main · Chemistry ↓ Falling

Biomolecules appeared 36 times across 3 years — 4.2% of Chemistry. This question is from Nucleic Acids (DNA and RNA).

Year 2026 2025 2024 Total
Questions 9 19 8 36

The total number of correct statements, regarding the nucleic acids is A. RNA is regarded as the reserve of genetic information. B. DNA molecule self-duplicates during cell division C. DNA synthesizes proteins in the cell. D. The message for the synthesis of particular proteins is present in DNA E. Identical DNA strands are transferred to daughter cells.

Numerical Answer Type:
Enter a numerical value Answer: 3 to 3 +4 marks

Solution & Explanation

Core Logic

A. RNA is regarded as the reserve of genetic information. (False - DNA is the reserve of genetic information). B. DNA molecule self-duplicates during cell division. (True - through replication). C. DNA synthesizes proteins in the cell. (False - RNA molecules synthesize proteins via translation, DNA only provides the code). D. The message for the synthesis of particular proteins is present in DNA. (True - the genetic code lies in the base sequence of DNA). E. Identical DNA strands are transferred to daughter cells. (True - through accurate replication and cell division, genetic continuity is maintained).

Step 1: Final Conclusion

The true statements are B, D, and E. Total number of correct statements is 3.

Chapter Mix

Class 12 Chemistry: Biomolecules

Reference Study Guides

More Biomolecules Previous-Year Questions — Page 4

Q jee_main_2025_08_april_evening Amino Acids
The chemical structure of the amino acid Valine is monitored across different environments: Choose the correct option depicting the structures of products A and B under pH = 2 and pH = 10 conditions respectively.
Valine pH equilibrium conversion layout for Q39
The flowchart maps the structural modifications of Valine when treated at strongly acidic (pH = 2) versus basic (pH = 10) conditions.
Valine pH equilibrium conversion layout for Q39
The flowchart maps the structural modifications of Valine when treated at strongly acidic (pH = 2) versus basic (pH = 10) conditions.
  • A.
  • B.
  • C.
  • D.

Solution

Core Logic

Amino acids exhibit amphoteric behavior due to the simultaneously present basic amino (-NH₂) and acidic carboxyl (-COOH) functional groups:

  • At pH = 2 (Highly Acidic Medium):
  • The abundant concentration of hydronium ions (H^+) protonates the carboxylate ion back into its non-ionized acid state (-COO^- arrow -COOH), while the amine group remains securely protonated as an ammonium ion (-NH₃^+). Hence, product A exists purely as a cation.

  • At pH = 10 (Highly Basic Medium):
  • The high concentration of hydroxide ions (OH^-) abstracts protons from the system, deprotonating the carboxyl group into a carboxylate anion (-COO^-) and neutralizing the ammonium group back into a free amine fraction (-NH₂). Hence, product B exists purely as an anion.

    Protonation state structures of Valine across the pH spectrum
    The flowchart maps the structural modifications of Valine when treated at strongly acidic (pH = 2) versus basic (pH = 10) conditions.

Pattern Recognition

Acidic environments (low pH) force positive overall charges onto amino structures (cation form). Basic environments (high pH) drive a net negative structure (anion form). This simple rule makes picking Option (1) immediate.

Chapter Mix

Class 12 Chemistry: Biomolecules

Q29 jee_main_2025_29_jan_evening Amino Acids and Proteins
Identify the essential amino acids from below: (A) Valine (B) Proline (C) Lysine (D) Threonine (E) Tyrosine Choose the correct answer from the options given below:
  • A. (A), (C) and (D) only
  • B. (A), (C) and (E) only
  • C. (B), (C) and (E) only
  • D. (C), (D) and (E) only

Solution

Core Logic

Essential amino acids cannot be synthesized by the body and must be obtained from diet. From the given choices:

  • Valine (Essential)
  • Proline (Non-essential)
  • Lysine (Essential)
  • Threonine (Essential)
  • Tyrosine (Non-essential)
  • Hence, (A), (C), and (D) are the essential amino acids.

Pattern Recognition

Mnemonic for essential amino acids: TV TILL PM MALL (Threonine, Valine, Tryptophan, Isoleucine, Leucine, Lysine, Phenylalanine, Methionine, Arginine, Histidine).

Chapter Mix

Class 12 Chemistry: Biomolecules

Q45 jee_main_2025_28_jan_morning Reactions of Glucose and Starch
Given below are two statements : Statement I : D-glucose pentaacetate reacts with 2, 4-dinitrophenylhydrazine. Statement II : Starch, on heating with concentrated sulfuric acid at 100°C and 2-3 atmosphere pressure produces glucose. In the light of the above statements, choose the correct answer from the options given below
  • A. Both Statement I and Statement II are false
  • B. Statement I is false but Statement II is true.
  • C. Statement I is true but Statement II is false.
  • D. Both Statement I and Statement II are true.

Solution

Core Logic

Statement I is false because glucose pentaacetate fixes the cyclic hemiacetal system structure securely into an unreactive ester configuration. As a result, it cannot revert to an open-chain form containing a free aldehyde group, meaning it does not react with carbonyl reagents like 2,4-DNP.

Statement II is true because starch, a polysaccharide composed of glucose monomer blocks, undergoes acid-catalyzed hydrolysis to yield glucose when heated under pressure.

Pattern Recognition

Sees: Pentacetate reactivity vs polysaccharide hydrolysis. Shortcut: Acetylation locks the cyclic structure of glucose, preventing reactions that require an open-chain carbonyl group (like 2,4-DNP).

Chapter Mix

Class 12 Chemistry: Biomolecules

Q31 jee_main_2025_03_april_morning Carbohydrate Structures
Which of the following is the correct structure of L-fructose?
  • A. Structure (1)
  • B. Structure (2)
  • C. Structure (3)
  • D. Structure (4)

Solution

Related Formula

D- and L-enantiomers are non-superimposable mirror images of each other at all chiral centers.

Core Logic

D-fructose has the -OH group at C-5 positioned on the right in its Fischer projection. L-fructose is the exact enantiomer (mirror image) of D-fructose, meaning all chiral centers (C-3, C-4, C-5) have inverted configurations, with the -OH group at C-5 on the left.

Step 1: Structural Verification

Structure (3) correctly displays the Fischer projection of L-fructose with C-3 -OH on the right, and C-4, C-5 -OH groups on the left.

Pattern Recognition

L-isomer is the exact mirror image of the D-isomer across all stereocenters.

Chapter Mix

Class 12 Chemistry: Biomolecules

Q jee_main_2025_04_april_evening Amino Acids and Peptides
A dipeptide, "x" on complete hydrolysis gives "y" and "z". "y" on treatment with aq. HNO₂ produces lactic acid. On the other hand "z" on heating gives the following cyclic molecule. Based on the information given, the dipeptide X is:
Cyclic molecule from dipeptide residue heating for Q29 - JEE Main 2025 Evening
The image shows a heterocyclic six-membered cyclic molecule containing amide groups, formed by heating amino acid residue z.
Cyclic molecule from dipeptide residue heating for Q29 - JEE Main 2025 Evening
The image shows a heterocyclic six-membered cyclic molecule containing amide groups, formed by heating amino acid residue z.
  • A. valine-glycine
  • B. alanine-glycine
  • C. valine-leucine
  • D. alanine-alanine

Solution

Related Formula
Dipeptide X Hydrolysis Amino Acid y + Amino Acid z
Core Logic
  • Since y reacts with nitrous acid (HNO₂) to give lactic acid (CH₃-CH(OH)-COOH), y must be alanine (CH₃-CH(NH₂)-COOH).
  • When glycine (NH₂-CH₂-COOH) is heated, two molecules undergo intermolecular cyclization to produce a six-membered diketopiperazine ring as shown in the problem diagram. Therefore, z is glycine.
  • Hence, combining residue y (alanine) and z (glycine), the dipeptide X is alanine-glycine.

Step 1: Stepwise Degradation Overview

Reaction scheme:

  • Alanine-Glycine linkage arrow Alanine + Glycine
  • Alanine + HNO₂ arrow Lactic acid + N₂ + H₂O
  • 2 × Glycine Δ Cyclic diketopiperazine + 2H₂O
Pattern Recognition

Lactic acid generation from alpha-amino acids via nitrous acid deamination is a definitive chemical fingerprint for alanine. The unsubstituted cyclic diketopiperazine product confirms glycine as the second component.

Chapter Mix

Class 12 Chemistry: Biomolecules

More Biomolecules Questions — jee_main_2024_30_january_evening

Practice all Biomolecules previous-year questions →

Rankbit System
JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%) | JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%)