Match List-I with List-II.

List-I (Reaction of glucose with)	List-II (Product formed)
A. Hydroxylamine	I. Gluconic acid
B. Br_2$Br_2$ water	II. Glucose pentaacetate
C. Excess acetic anhydride	III. Saccharic acid
D. Concentrated HNO_3$HNO_3$	IV. Glucoxime

Choose the correct answer from the options given below:

### Core Logic A. Arginine and Tryptophan are indeed essential amino acids (cannot be synthesized by the human body). (Correct) B. Histidine contains an imidazole ring, which is a heterocyclic ring. So statement B is incorrect. C. Proline contains a pyrrolidine ring, which is a five-membered cyclic ring. So statement C is incorrect. D. Glycine is mathrmNH_2-CH_2-COOH$\mathrm{NH_2-CH_2-COOH}$. Because its alpha carbon has two identical hydrogen atoms attached, it lacks a chiral center. (Correct) E. Cysteine's side chain is a thiol group (-mathrmCH_2-SH$-\mathrm{CH_2-SH}$), not a thioether (mathrmMeS-CH_2-CH_2-$\mathrm{MeS-CH_2-CH_2-}$ which belongs to Methionine). So statement E is incorrect. Correct statements: A and D. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Chemistry: Biomolecules

### Core Logic - A is correct: Enzymes lower activation energy significantly. - B is correct: Denaturation affects secondary and tertiary structures while primary structure remains intact. - C is incorrect: Nucleotides are joined by phosphodiester linkages, and glycosidic linkages connect bases to sugars. - D is incorrect: Quaternary structure represents aggregation of multiple polypeptide subunits, not single chain folding. ### Step 1: Final Conclusion Only statements A and B are correct, matching option (3). ### Pattern Recognition Sees: Biomolecules structural and enzymatic properties. Trap: Confusing primary structure disruption with denaturation. ### Chapter Mix Class 12 Chemistry: Biomolecules

### Related Formula C_12H_22O_11 + H_2O xrightarrowH^+ Dtext-Glucose + Dtext-Fructose$$C_{12}H_{22}O_{11} + H_2O \xrightarrow{H^+} D\text{-Glucose} + D\text{-Fructose}$$ ### Core Logic Statement I: Pure sucrose has a specific rotation [alpha]_D = +66.5^circ$[\alpha]_D = +66.5^{\circ}$, so it is dextrorotatory. Upon hydrolysis, it forms an equimolar mixture of D-glucose and D-fructose. The net specific rotation of the mixture is negative, resulting in laevorotation. (This is called inversion of sugar). Statement I is true. Statement II: Hydrolysis gives glucose and fructose. The specific rotation of D-glucose is +52.5^circ$+52.5^{\circ}$ (dextrorotation), while that of D-fructose is -92.4^circ$-92.4^{\circ}$ (laevorotation). The statement claims that glucose is laevorotatory and fructose is dextrorotatory, which is strictly backward. Therefore, Statement II is false. ### Step 1: Final Conclusion Statement I is true but Statement II is false. ### Pattern Recognition Invert sugar concepts are very common. Always verify which monomer rotates light in which direction. D-fructose is strongly laevorotatory (-92.4^circ$-92.4^{\circ}$). ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Chemistry: Biomolecules

### Related Formula textNumber of unique sequences = n!$$\text{Number of unique sequences} = n!$$ ### Core Logic A **tetrapeptide** is formed by connecting four amino acids through three peptide linkages. Since the problem specifies that complete hydrolysis of the tetrapeptide produces Gly, Ala, Val, and Leu in *equimolar proportions*, the peptide must contain exactly one molecule of each of these four distinct amino acids. ### Step 1: Calculate the Permutations The number of unique peptide sequences corresponds to the number of ways we can arrange these 4 distinct amino acids: textNumber of permutations = 4! = 4 times 3 times 2 times 1 = 24$$\text{Number of permutations} = 4! = 4 \times 3 \times 2 \times 1 = 24$$ ### Pattern Recognition Combinatorics in Chemistry: If we have n$n$ unique, non-repeating amino acids, the number of linear isomeric peptides is n!$n!$. If repetition were permitted, the number of possible peptides would be n^n$n^n$ (which would be 4^4 = 256$4^4 = 256$ in this case). ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 12 Chemistry: Biomolecules