Solution
Related Formula
I = I₀ ²((Δφ)/(2)) Δφ = (2π)/(λ) Δ xCore Logic
Where Δ x = λ, the phase difference Δφ = 2π. Intensity I = I₀ ²((2π)/(2)) = I₀ ²(π) = I₀. We are given that at this point, Intensity = K. Thus, I₀ = K.
Step 1: Calculate Intensity at new path difference
Now evaluate at Δ x = (λ)/(3). The phase difference is:
Δφ = (2π)/(λ) × (λ)/(3) = (2π)/(3)Substitute this into the intensity formula:
I₁ = I₀ ²((2π/3)/(2)) = I₀ ²((π)/(3))Since ((π)/(3)) = (1)/(2):
I₁ = I₀ ((1)/(2))² = (I₀)/(4)Since I₀ = K, we get:
I₁ = (K)/(4)Pattern Recognition
In YDSE, phase angle is strictly mapped to path difference λ → 2π. The square of the cosine half-angle dictates the final intensity drop.
Chapter Mix
Class 12 Physics: Wave Optics