Each side of a metallic cube of mass 5.580 ~kg$5.580 \mathrm{~kg}$ is measured to the 9.0 ~cm$9.0 \mathrm{~cm}$. Keeping the significant figures in view, the density of the material of the cube can be best expressed as X × 10³ ~kg m⁻³$X \times 10^{3} \mathrm{~kg \ m^{-3}}$ where the value of X$X$ is:

Related Formula

d = v × t$d = v \times t$

Core Logic

Given the speed of light v = 1$v = 1$ (new unit of distance per second). Time taken t = 6 ~min 40 ~s$t = 6 \mathrm{~min} \ 40 \mathrm{~s}$.

Convert time entirely into seconds:

Step 1: Calculate Distance

Using the kinematic relation d = vt$d = vt$:

Pattern Recognition

Whenever "speed is taken as unity", distance simply becomes numerically equal to the time measured in base units (seconds).

Chapter Mix

Class 11 Physics: Units and Measurements

Related Formula

Core Logic

Given: 1 MSD = 1 ~mm$1 \text{ MSD} = 1 \mathrm{~mm}$ 20 VSD = 16 MSD$20 \text{ VSD} = 16 \text{ MSD}$

Find the value of 1 VSD$1 \text{ VSD}$:

Step 1: Compute Least Count

Substitute the value of 1 MSD$1 \text{ MSD}$:

Step 2: Convert Units

Convert millimeters to centimeters to match the options:

Pattern Recognition

L.C. is strictly the difference between 1 Main Scale Division and 1 Vernier Scale Division. Always be careful about final units (cm vs mm).

Chapter Mix

Class 11 Physics: Units and Measurements