Keeping the significant figures in view, the sum of the physical quantities 52.01 text m$52.01 \text{ m}$, 153.2 text m$153.2 \text{ m}$ and 0.123 text m$0.123 \text{ m}$ is :

### Related Formula Addition Rule for Significant Figures: The result cannot have more digits to the right of the decimal point than any of the original numbers. ### Core Logic Let's align the numbers and perform exact addition: 52.01$52.01$ (2 decimal places) 153.2$153.2$ (1 decimal place - least precise) + 0.123$+ 0.123$ (3 decimal places) -------- 205.333$205.333$ ### Step 1: Final Conclusion According to the rules of significant figures for addition, the sum must be rounded to the least number of decimal places present in the given measurements. Here, 153.2$153.2$ has only 1$1$ decimal place. Rounding 205.333$205.333$ to one decimal place yields 205.3 text m$205.3 \text{ m}$. ### Pattern Recognition Addition/Subtraction is bounded by decimal places. Multiplication/Division is bounded by total significant figures. In this case, 1 decimal place rules. ### Evaluation Rubric / Model Answer null ### Chapter Mix Class 11 Physics: Units and Measurements