NEET · Chemistry —

Hydrogen appeared 1 time across 1 year — 2.2% of Chemistry. This question is from Preparation of Dihydrogen.

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Questions 1 1
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Methane reacts with steam at 1273 K in the presence of nickel catalyst to form:

Solution & Explanation

Related Formula
CH₄(g) + H₂O(g) [Δ]Ni CO(g) + 3H₂(g)
Core Logic

This reaction is the classic industrial method for the preparation of Synthesis gas (Syngas) or Water gas. Methane reacts with steam at high temperatures (around 1273 K) over a nickel catalyst to yield a mixture of carbon monoxide and hydrogen gas.

Step 1: Final Conclusion

The products formed are CO and H₂.

Pattern Recognition

Steam reforming of hydrocarbons (especially methane) over a Nickel catalyst is the textbook method for producing syngas (CO + H₂).

Chapter Mix

Class 11 Chemistry: Hydrogen Class 11 Chemistry: Hydrocarbons

Reference Study Guides

Hydrogen
Rankbit System
JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%) | JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%)