Q71 (2024)
Methane reacts with steam at 1273 K in the presence of nickel catalyst to form:
- CO and $H_{2}$
- CO and $H_{2}O$
- $CO_{2}$ and $H_{2}O$
- CO2 and $H_{2}$
### Related Formula
$$\mathrm{CH_4(g)} + \mathrm{H_2O(g)} \xrightarrow[\Delta]{Ni} \mathrm{CO(g)} + 3\mathrm{H_2(g)}$$
### Core Logic
This reaction is the classic industrial method for the preparation of Synthesis gas (Syngas) or Water gas.
Methane reacts with steam at high temperatures (around 1273 K) over a nickel catalyst to yield a mixture of carbon monoxide and hydrogen gas.
### Step 1: Final Conclusion
The products formed are CO and $H_2$.
### Pattern Recognition
Steam reforming of hydrocarbons (especially methane) over a Nickel catalyst is the textbook method for producing syngas ($CO + H_2$).
### Evaluation Rubric / Model Answer
null
### Chapter Mix
Class 11 Chemistry: Hydrogen
Class 11 Chemistry: Hydrocarbons
