The enzyme required for carboxylation in the Calvin cycle is

Related Formula

1 turn of Calvin Cycle (fixes 1 CO₂) = 3 ATP + 2 NADPH$1 \text{ turn of Calvin Cycle (fixes } 1 \text{ CO}_2\text{)} = 3 \text{ ATP} + 2 \text{ NADPH}$ 1 Glucose (C₆H₁₂O₆) = 6 turns of Calvin Cycle$1 \text{ Glucose } (C_6H_{12}O_6) = 6 \text{ turns of Calvin Cycle}$

Core Logic

To synthesize 1 molecule of glucose, 6 turns of the Calvin cycle are required:

Step 1: Calculation

Hence, 18 ATP and 12 NADPH molecules are required for 1 glucose molecule.

Pattern Recognition

Calvin Cycle ratio per CO₂$CO_2$: 3 ATP : 2 NADPH. For 6 CO₂$CO_2$ (Glucose): 6 × 3 = 18$6 \times 3 = 18$ ATP and 6 × 2 = 12$6 \times 2 = 12$ NADPH.

Chapter Mix

Class 11 Biology: Photosynthesis in Higher Plants

Related Formula

Water splitting complex = Associated with PS-II (lumen side). Kranz Anatomy = Exclusive feature of C₄$C_4$ plants.

Core Logic

• Statement A is incorrect: Water splitting complex is located on the inner side of PS-II membrane, not PS-I.
• Statement B is correct: Both C₃$C_3$ and C₄$C_4$ plants utilize Calvin cycle (C₃$C_3$ pathway) for sugar synthesis.
• Statement C is correct: C₄$C_4$ plants avoid photorespiration by maintaining high CO₂$CO_2$ at RuBisCO site.
• Statement D is incorrect: Kranz anatomy is shown by C₄$C_4$ plants, not C₃$C_3$ plants.
• Statement E is correct: Photophosphorylation in chloroplasts occurs via chemiosmotic hypothesis.

Step 1: Selection

Incorrect statements are A and D. Option (2) is correct.

Pattern Recognition

Water splitting = PS II (A is False). Kranz anatomy = C₄$C_4$ plants (D is False). Incorrect statements = A and D.

Chapter Mix

Class 11 Biology: Photosynthesis in Higher Plants