NEET · Biology —

Photosynthesis in Higher Plants appeared 3 times across 1 year — 3.3% of Biology. This question is from Calvin Cycle Stoichiometry.

Year 2024 Total
Questions 3 3

How many ATP and NADPH molecules are required to make one molecule of glucose through the Calvin pathway?

Solution & Explanation

Related Formula

1 turn of Calvin Cycle (fixes 1 CO₂) = 3 ATP + 2 NADPH 1 Glucose (C₆H₁₂O₆) = 6 turns of Calvin Cycle

Core Logic

To synthesize 1 molecule of glucose, 6 turns of the Calvin cycle are required:

Total ATP = 6 × 3 = 18 ATP Total NADPH = 6 × 2 = 12 NADPH
Step 1: Calculation

Hence, 18 ATP and 12 NADPH molecules are required for 1 glucose molecule.

Pattern Recognition

Calvin Cycle ratio per CO₂: 3 ATP : 2 NADPH. For 6 CO₂ (Glucose): 6 × 3 = 18 ATP and 6 × 2 = 12 NADPH.

Chapter Mix

Class 11 Biology: Photosynthesis in Higher Plants

Reference Study Guides

More Photosynthesis in Higher Plants Previous-Year Questions

Q108 neet_2024_05_may_morning Photosynthetic Adaptations
Find the incorrect statement(s) about photosynthesis from the following: A. The water splitting complex is associated with PS I. B. C₄ plants use the C₃ pathway of CO₂ fixation as the main biosynthetic pathway. C. In C₄ plants, photorespiration does not occur. D. C₃ plants exhibit 'Kranz' anatomy. E. ATP synthesis in chloroplast occurs through chemiosmosis. Choose the answer from the options given below:
  • A. B only
  • B. A and D only
  • C. B and C only
  • D. B and E only

Solution

Related Formula

Water splitting complex = Associated with PS-II (lumen side). Kranz Anatomy = Exclusive feature of C₄ plants.

Core Logic
  • Statement A is incorrect: Water splitting complex is located on the inner side of PS-II membrane, not PS-I.
  • Statement B is correct: Both C₃ and C₄ plants utilize Calvin cycle (C₃ pathway) for sugar synthesis.
  • Statement C is correct: C₄ plants avoid photorespiration by maintaining high CO₂ at RuBisCO site.
  • Statement D is incorrect: Kranz anatomy is shown by C₄ plants, not C₃ plants.
  • Statement E is correct: Photophosphorylation in chloroplasts occurs via chemiosmotic hypothesis.
Step 1: Selection

Incorrect statements are A and D. Option (2) is correct.

Pattern Recognition

Water splitting = PS II (A is False). Kranz anatomy = C₄ plants (D is False). Incorrect statements = A and D.

Chapter Mix

Class 11 Biology: Photosynthesis in Higher Plants

Q132 neet_2024_05_may_morning Calvin Cycle Enzymes
The enzyme required for carboxylation in the Calvin cycle is
  • A. PEP carboxylase
  • B. RuBP carboxylase - oxygenase
  • C. Carboxypeptidase
  • D. Hexokinase

Solution

Related Formula
RuBP + CO₂ + H₂O RuBisCO 2 × 3-PGA
Core Logic

The first step of the Calvin cycle is carboxylation, where CO₂ is fixed onto Ribulose-1,5-bisphosphate (RuBP) catalyzed by the enzyme RuBP carboxylase-oxygenase (RuBisCO).

Step 1: Selection

The required enzyme is RuBP carboxylase - oxygenase. Option (2) is correct.

Pattern Recognition

Carboxylation enzyme in Calvin Cycle = RuBisCO (RuBP carboxylase-oxygenase).

Chapter Mix

Class 11 Biology: Photosynthesis in Higher Plants

More Photosynthesis in Higher Plants Questions — neet_2024_05_may_morning

Practice all Photosynthesis in Higher Plants previous-year questions →

Rankbit System
JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%) | JEE Physics: Waves (+15.5%) | Electrostatics: Concentric Shells (-29.7%) | Modern Physics: Photoelectric Clones (+34.2%) | Mathematics: Definite Integrals (+18.1%) | Chemistry: Coordination Splitting (-11.4%)