Match List-I with List-II. List-I (Respiratory Volume) List-II (Capacity in mL) A. ERV (Expiratory Reserve Volume) I…

Q: Match List-I with List-II. List-I (Respiratory Volume) List-II (Capacity in mL) A. ERV (Expiratory Reserve Volume) I. 2500 – 3000 mL B. RV (Residual Volume) II. 500 mL C. IRV (Inspiratory Reserve Volu

From standard human respiratory volumes: - Tidal Volume (TV) is the volume of air inspired/expired during normal respiration = approx. 500 mL (D-II). - Inspiratory Reserve Volume (IRV) is the extra air a person can inspire forcefully = 2500 - 3000 mL (C-I). - Expiratory Reserve Volume (ERV) is the extra air a person can expire forcefully = 1000 - 1100 mL (A-III). - Residual Volume (RV) is the air remaining in the lungs even after forceful expiration = 1100 - 1200 mL (B-IV). The correct matches a

Year	2024	Total
Questions	3	3

Year

2024

Total

Questions

List-I (Respiratory Volume)	List-II (Capacity in mL)
A. ERV (Expiratory Reserve Volume)	I. 2500 – 3000 mL
B. RV (Residual Volume)	II. 500 mL
C. IRV (Inspiratory Reserve Volume)	III. 1000 – 1100 mL
D. TV (Tidal Volume)	IV. 1100 – 1200 mL

List-I (Respiratory Volume)

List-II (Capacity in mL)

A. ERV (Expiratory Reserve Volume)

I. 2500 – 3000 mL

B. RV (Residual Volume)

II. 500 mL

C. IRV (Inspiratory Reserve Volume)

III. 1000 – 1100 mL

D. TV (Tidal Volume)

IV. 1100 – 1200 mL

Solution & Explanation

Core Logic

From standard human respiratory volumes:

Tidal Volume (TV) is the volume of air inspired/expired during normal respiration = approx. $500 mL$ $500 \text{ mL}$ (D-II).
Inspiratory Reserve Volume (IRV) is the extra air a person can inspire forcefully = $2500 - 3000 mL$ $2500 - 3000 \text{ mL}$ (C-I).
Expiratory Reserve Volume (ERV) is the extra air a person can expire forcefully = $1000 - 1100 mL$ $1000 - 1100 \text{ mL}$ (A-III).
Residual Volume (RV) is the air remaining in the lungs even after forceful expiration = $1100 - 1200 mL$ $1100 - 1200 \text{ mL}$ (B-IV).

Step 1: Final Conclusion

The correct matches are A-III, B-IV, C-I, D-II.

Pattern Recognition

TV is the smallest base volume ( $500 mL$ $500 \text{ mL}$). Connecting D to II instantly narrows the choices down. IRV is the largest ( $2500 - 3000 mL$ $2500 - 3000 \text{ mL}$). Connecting C to I leaves only one valid option.

Chapter Mix

Class 11 Biology: Breathing and Exchange of Gases

More Breathing and Exchange of Gases Previous-Year Questions

Q160 neet_2026_03_may_morning Human Respiratory System

In humans, respiration occurs in the following steps. Arrange these steps in the correct order. A. Diffusion of

O₂

and

CO₂

between blood and tissues B. Diffusion of

O₂

and

CO₂

across alveolar membrane C. Pulmonary ventilation by which atmospheric air is drawn in and

CO₂

rich alveolar air is released out D. Cellular respiration E. Transport of gases by the blood Choose the correct answer from the options given below

A. A, B, C, D, E
B. E, A, C, D, B
C. C, A, B, E, D
D. C, B, E, A, D

Solution

Core Logic

Respiration involves the following sequential steps: (i) Breathing or pulmonary ventilation by which atmospheric air is drawn in and $CO₂$ $CO_{2}$ rich alveolar air is released out (C). (ii) Diffusion of gases across alveolar membrane (B). (iii) Transport of gases by the blood (E). (iv) Diffusion of $O₂$ $O_{2}$ and $CO₂$ $CO_{2}$ between blood and tissues (A). (v) Utilisation of $O₂$ $O_{2}$ by the cells for catabolic reactions and resultant release of $CO₂$ $CO_{2}$ (Cellular respiration) (D).

Step 1: Final Conclusion

The correct order is C $arrow$ $\rightarrow$ B $arrow$ $\rightarrow$ E $arrow$ $\rightarrow$ A $arrow$ $\rightarrow$ D.

Pattern Recognition

Follow the physical path of oxygen: Environment $arrow$ $\rightarrow$ Lungs (Ventilation) $arrow$ $\rightarrow$ Alveolar Blood (Diffusion) $arrow$ $\rightarrow$ Systemic Blood (Transport) $arrow$ $\rightarrow$ Tissues (Diffusion) $arrow$ $\rightarrow$ Mitochondria (Cellular).

Chapter Mix

Class 11 Biology: Breathing and Exchange of Gases

Q177 neet_2026_03_may_morning Respiratory Organs

Match List I with List II:

List I	List II
A. Molluscs	I. Pulmonary respiration only
B. Reptiles	II. Branchial respiration
C. Adult amphibians	III. Cellular respiration
D. Amoeba	IV. Pulmonary and cutaneous respiration

Choose the correct answer from the options given below:

A. A-III, B-II, C-I, D-IV
B. A-II, B-I, C-IV, D-III
C. A-II, B-I, C-III, D-IV
D. A-I, B-II, C-IV, D-III

Solution

Core Logic

(A) Molluscs $arrow$ $\rightarrow$ (II) Perform branchial respiration by using feather-like gills. (B) Reptiles $arrow$ $\rightarrow$ (I) Perform pulmonary respiration only via lungs. (C) Adult amphibians $arrow$ $\rightarrow$ (IV) Perform pulmonary and cutaneous respiration via lungs and moist skin, respectively. (D) Amoeba $arrow$ $\rightarrow$ (III) Performs cellular respiration across its body surface to generate ATP for survival.

Step 1: Final Conclusion

Thus, the matching is (A) - II, (B) - I, (C) - IV, (D) - III.

Pattern Recognition

Adult amphibians exhibit dual modes of respiration (lungs and skin). Reptiles only use lungs. Aquatic molluscs use gills (branchial).

Chapter Mix

Class 11 Biology: Breathing and Exchange of Gases Class 11 Biology: Animal Kingdom

Solution & Explanation

Core Logic

Step 1: Final Conclusion

Pattern Recognition

Chapter Mix

Reference Study Guides

More Breathing and Exchange of Gases Previous-Year Questions

Solution

Core Logic

Step 1: Final Conclusion

Pattern Recognition

Chapter Mix

Solution

Core Logic

Step 1: Final Conclusion

Pattern Recognition

Chapter Mix

More Breathing and Exchange of Gases Questions — neet_2026_03_may_morning

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Step 1: Final Conclusion

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Reference Study Guides

More Breathing and Exchange of Gases Previous-Year Questions

Solution

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Solution

Core Logic

Step 1: Final Conclusion

Pattern Recognition

Chapter Mix

More Breathing and Exchange of Gases Questions — neet_2026_03_may_morning

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